5
votes
Deleting all text after a specific string for multiple text files in a directory
Using jq (available for most Unix-like systems), you could extract the first JSON object from a file and discard the rest using
jq -n 'input' file >newfile
This produces "pretty-printed" ...
- 271k
5
votes
Write a regular expression whose output will only be rows in a range 01/03/2021 - 01/03/2020
Using the example file given, where dates are in order and the start + end date are present in the file, you might find a solution using awk to be more straightforward.
$ awk '$1=="01/03/2020&...
- 20.1k
4
votes
awk/sed find indexes of the first and the last capital letter in a string
$ awk '
match($0,/[[:upper:]](.*[[:upper:]])?/) {
print $0, RSTART, length()-(RSTART+RLENGTH-2)
}
' file
xyzAb 4 2
--AbbbAnde--- 3 7
abksjiRNNBBKUGFLYFYLF 7 1
-ankNUGUYUBUIGCafrg-- 5 7
...
- 22.5k
4
votes
Accepted
awk/sed find indexes of the first and the last capital letter in a string
awk '
{
start = match($0, /[A-Z]/)
end = match($0, /[A-Z][^A-Z]*$/)
print (start ? start : "NaN"), (end ? length() - end + 1 : "NaN")
}' infile
- 38.4k
3
votes
awk/sed find indexes of the first and the last capital letter in a string
It is easy to get the length of the leading or trailing part with AWK. Add 1 to get the index as shown in the question.
echo '--AbbbAnde---
abksjiRNNBBKUGFLYFYLF
-ankNUGUYUBUIGCafrg--
BNKJUGFVULNK-Kew-...
- 5,433
2
votes
Write a regular expression whose output will only be rows in a range 01/03/2021 - 01/03/2020
From your description you need any date from year 2020 after 01/03/2020. That would be:
$ egrep "(../(0[3-9]|1[0-2])/2020$)" dates.txt
And also all dates from 2021 up to 01/03/2021. That ...
2
votes
Accepted
Find missing values of column 1, then add those values and assign column 2 as 0
I don't usually offer code answers when there's been no obvious attempt. However, today it's sunny and here's my suggestion,
awk '
{
this = int($1*100 + .5) # Counter is ...
- 90.2k
2
votes
Write a regular expression whose output will only be rows in a range 01/03/2021 - 01/03/2020
Using Raku (formerly known as Perl_6)
raku -ne 'my $ts = .subst(/ ^ (\d**2) \/ (\d**2) \/ (\d**4) /, {"$2-$1-$0"}).Date; say $ts if Date.new("2020-03-01") < $ts < Date.new
(&...
- 1,220
2
votes
Replace values in fifth column
Okay, unfortunally, sed doesn't know that 10 is John. So if you don't want to write another substitution for each user, you might want to use a second file users.txt with a translation table like this:...
- 11.6k
2
votes
Replace values in fifth column
awk 'gsub(/0/, "", $5) { print $1, $2, $3, $4, "user" $5 }' INPUT
gsub removes number "0" in the 5th column. Then awk prints column 1-4, and combines word "user&...
2
votes
Replace values in fifth column
Two more awk solutions.
$ awk '{$5="user"substr($5,1,1)}1' file
Name 1:10:34 date short_id user1
Name 1:10:45 date short_id user1
Name 1:20:54 date short_id user2
Name 1:30:43 date short_id ...
- 20.1k
2
votes
Using AWK to sum up two column for each block
$ cat tst.awk
BEGIN { FS=SUBSEP=";"; OFS=" = " }
NF == 0 { prt(); delete sum }
{ print }
NF > 3 { sum[$4,$5]++ }
END { prt() }
function prt( key) {
for ( key in sum ) {
...
- 22.5k
2
votes
awk/sed find indexes of the first and the last capital letter in a string
Using Raku (formerly known as Perl_6)
Sample Input:
--AbbbAnde---
abksjiRNNBBKUGFLYFYLF
-ankNUGUYUBUIGCafrg--
BNKJUGFVULNK-Kew---
nouppercaseletters
oneUppercaseletter
Skips lines with 0 or 1 ...
- 1,220
2
votes
Accepted
Write a regular expression whose output will only be rows in a range 01/03/2021 - 01/03/2020
I really wouldn't try to do this with just regular expressions. More sophisticated tools will make it easier. For example, with awk:
$ awk -F/ '($3==2020 && $2 > 2) || ($3==2021 && (...
- 216k
2
votes
How to convert aggregated data to narrow 2 columns table by the first column of numbers
Awk solution
An awk executable file conv_table.awk:
#! /usr/bin/awk -f
{
# for all fields after the first column
for (idx = 2; idx <= NF; idx++) {
# print first column followed by ...
- 285
1
vote
awk/sed find indexes of the first and the last capital letter in a string
GNU awk with field delimiter as an uppercase regex.
LC_ALL=C \
awk -F '[A-Z]' '
NF>2{
print length("x"$1), length("x"$NF)
}' file
Perl has index & rindex builtins to get ...
- 5,398
1
vote
awk/sed find indexes of the first and the last capital letter in a string
{
s = match($0, /[A-Z]/); pad = RSTART
clone = substr($0, RSTART + 1)
while (match(clone, /[A-Z]/)) {
clone = substr(clone, RSTART + 1)
pad += RSTART
}
print $0, &...
- 2,400
1
vote
Get value from a key value pair separated with pipe
With zsh instead of bash, storing the result in an associative array:
$ string='Delete :xna.del|mode:Full|Execution: loaded'
$ IFS=':|'
$ set -o extendedglob
$ typeset -A field=( ${=string//[[:space:]]...
- 470k
1
vote
Replace values in fifth column
Using Raku (formerly known as Perl_6)
raku -ne 'given .words -> $w {put "$w.[0..3] ", (S/ (\d+) /user{$0.substr(0,1)}/ with $w.[4]) };'
OR
raku -ne 'put .[0..3], " ", (S/ (\d+) ...
- 1,220
1
vote
Ansible - How to reboot the server based on condition?
Please take note that a restart may be required not only after installing a new kernel but also after updates of microcode, glibc, SSL libs, etc.. So some more events will require a restart and needs ...
- 765
1
vote
Replace values in fifth column
Just use awk:
$ awk '!($NF in users){ users[$NF]="user"(++cnt) } { $NF=users[$NF] } 1' file
Name 1:10:34 date short_id user1
Name 1:10:45 date short_id user1
Name 1:20:54 date short_id user2
...
- 22.5k
1
vote
Replace values in fifth column
Using sed
sed 's/\(.*\) \(.\).*/\1 user\2/' input_file
Name 1:10:34 date short_id user1
Name 1:10:45 date short_id user1
Name 1:20:54 date short_id user2
Name 1:30:43 date short_id user3
Name 1:40:43 ...
- 1,139
1
vote
Replace values in fifth column
If all you want to change is the last column you don't need the g modifier for global and you will want to add the $ anchor to limit it to the last column.
I.e.: sed 's/\b10$/user1/'
That is assuming ...
- 2,289
1
vote
Write a regular expression whose output will only be rows in a range 01/03/2021 - 01/03/2020
Just use awk:
$ awk -F'/' '{d=$3$2$1} (20200301 <= d) && (d <= 20210301)' dates.txt
01/03/2020
13/03/2020
14/04/2020
29/05/2020
16/06/2020
17/07/2020
18/08/2020
19/09/2020
20/10/2020
21/...
- 22.5k
1
vote
Remove all characters from string, except specific multibyte range
Using Raku (formerly known as Perl_6)
Sample Input (OP's text saved as a one-line file):
~$ cat peace.txt
Peace be upon you. السلام عليكم. שלום עליכם. Paz sobre vosotros.
Extract Arabic script:
~$ ...
- 1,220
1
vote
Accepted
Remove all characters from string, except specific multibyte range
You can use Unicode properties in Perl:
echo "Peace be upon you. السلام عليكم. שלום עליכם. Paz sobre vosotros." \
| perl -CIO -pe 's/\P{Arabic}//g'
-CIO tells Perl that input and output are ...
- 42.6k
1
vote
How to parse a particular ids from a text file?
Perl 5 solution
$ perl -nle 'print join"\n",m/uniprot\":\"(.*?)\"/g' file.txt
P12807
P12807
T12807
P12808
Z12809
P12821
P0C918
$
- 20.1k
Only top scored, non community-wiki answers of a minimum length are eligible