New answers tagged grep
0
votes
Accepted
How to jump to the file and line of the grep -nr output?
Moved from the question to an answer
I came up with this solution. It's not elegant and short (and also assumes that only one occurrence is found, but could be expanded on this), but does the job.
res=...
-1
votes
Identifying genes from a list of genes
You can also use grep command in linux,by giving command like egrep -wi "complete genelist (1) with inducing pipe among genes" "file name containg all genes(2)".Here genelist(1) is ...
13
votes
Accepted
tr command unable to process colour output piped from grep
To output matches in colour, grep writes colouring escape sequences before and after the match.
Those are instructions to the terminals to change their background and/or foreground colour.
It's ...
- 466k
1
vote
tr command unable to process colour output piped from grep
I fixed it by changing
GREP_OPTIONS from --color=always to --color=auto
I suppose tr and colour coded text don't go well together
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1
vote
return a list using grep (or alternative)
You could do something like this, in GNU awk:
gawk -F'[[:blank:]]*=[[:blank:]]*' -v key=Exec '
BEGINFILE {value = "0"}
$1 == key {value = $2; nextfile}
ENDFILE {split(value,v,/[[:...
- 72.1k
0
votes
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Extracting text with expressions from a text file using grep
This should do it for you:
:~$ cat event.log
18.05.2022 13:54:52 [ INFO]: Starting Component 'OWN_FUNDS_RULES' (5/15)
18.05.2022 14:28:22 [ INFO]: Finished Component 'OWN_FUNDS_RULES_CONSOLIDATION' (6/...
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2
votes
Looping through 'find' files and 'grep' to file character set result (standard input)
You're piping data into grep's stdin, so grep does not have a filename to print.
I'm assuming 2022* are the filenames, not directories.
find . -type f -name '2022*' -exec sh -c '
for file; do
...
- 78k
5
votes
Looping through 'find' files and 'grep' to file character set result (standard input)
file is already printing the filename, you have to cut it after a simple grep. If your files are into the same directory:
file -i * | grep -v 'charset.*ascii' | cut -d: -f1
And if you match files ...
- 6,180
4
votes
Accepted
-bash: syntax error near unexpected token `(' when using lookahead and lookback?
The issue that the error message addresses is not the single quotes but the parentheses. Unquoted parentheses are special to the shell, and their meaning depends on their placement on the command ...
- 267k
0
votes
How to remove line with specific string from file
If that is the exact contents of the file, then here is an easy solution with GNU sed:
sed '/^\/home\/user1\/$/d' file
^ marks the beginning of the line and $ marks the end of the line so it will ...
- 9,473
0
votes
How to remove line with specific string from file
If sed is an option
$ sed -n '\|\(/\([^/]*/\)\{2\}\)\<|p' input_file
/home/user1/dir1
/home/user1/dir2
/home/user1/dir1/dir11
- 1,092
1
vote
Accepted
How to remove line with specific string from file
Use anchors to mark the beginning and end of the line: ^ for the beginning and $ for the end. So it would go like this:
$ grep -v '^/home/user1/$' file
/home/user1/dir1
/home/user1/dir2
/home/user1/...
- 11.2k
1
vote
Find how many words in a file contain a number in them?
I suspect you're not getting any matches because your shell is interpreting the brackets using its own syntactic rules. They need to be in quotes. But even if it weren't for that problem, yours would ...
- 7,117
0
votes
grepping a variable and adding 1 to it
A bunch of partial answers:
How to handle a number with leading zero(s), v1:
newvar=$(printf '%s + 1\n' "$var" | bc)
or, equivalently,
newvar=$(bc <<< "$var + 1")
...
4
votes
Accepted
Do grep and cp treat "recursive" the same?
Your grep command,
grep -R "find me" *.php
... contains a filename globbing pattern, *.php. This will be expanded by the shell before the shell executes grep, so the actual command at ...
- 267k
0
votes
Command line - save sub-strings conditionally
Using sed
$ sed s'~\([0-9]\)/[^:]*:\(.*\)~echo \2 >> \1~e' file.txt
$ cat 1
20020711
20020731
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5
votes
Accepted
Command line - save sub-strings conditionally
With awk:
awk -F'[:/]' '{print $NF > $1}' file
We split the row using both / and : as separators. The last field ($NF) is what to print, and the first field ($1) is the output filename.
After ...
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1
vote
Accepted
Linux - count words with more than a certain length of characters
After you mentioned your professor, I'm a bit worried we're doing your homework for you, but you can try:
egrep -wo '[[:alnum:]]{5,}' filename.txt | wc -w
This looks for spans of 5 or more ...
- 7,117
2
votes
Accepted
Return content between corresponding brackets
What you've offered isn't valid JSON. Bracketing the expression, fixing up the other errors, and adding a counter-example:
{
"text": [
{
"string1": ["...
- 89k
0
votes
grepping a variable and adding 1 to it
I can achieve it but don't use grep function, code below:
#!/bin/bash
echo "enter number"
read number
newnumber=$((number + 1 + 10000)) # 10000 = the largest value
echo ${newnumber#*1}
- 9
0
votes
Accepted
How to add column based in the second line match using SED or another command?
How about the simple awk command:
$ awk -F "1 - |2 - Response:" 'NF>1 {printf "%s",$2} END{print ""}' input_file
URL Template: https://www.test.com <200 OK,{Server=[...
- 2,229
-1
votes
How to add column based in the second line match using SED or another command?
sed '/^$/d' filename| awk 'NR==2{gsub(/.*Response:/,"",$0)}1'|sed "1s/.*-//g"|perl -pne "s/\n/ /g"
output
URL Template: https://www.test.com <200 OK,{Server=[nginx],...
- 4,698
0
votes
How to add column based in the second line match using SED or another command?
Using sed
$ sed '/^1/{:a;N;s/^[^A-Z]*\(.*\)\n[^<]*\(.*\)/\1 \2/;ba}' input_file
URL Template: https://www.test.com <200 OK,{Server=[nginx], Date=[Wed, 11 May 2022 01:05:06 GMT], Content-Type=[...
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1
vote
Accepted
Extract field and number of occurrences per line
Try this:
$ awk -v FS="', '" '{print $4 " |"NF-1 " " NR}' file
If you have blank lines in file, you may want to use:
$ awk -v FS="', '" 'NF >= 1 {print $4 &...
- 2,229
0
votes
How to ignore all text containing special character more than once?
sed -n '/.*_.*_.*/!p' file.txt
output
apple_ig
dog_ig
orange_ig
goat_ig
- 4,698
0
votes
How to ignore all text containing special character more than once?
GNU sed we try to replace the second occurrence of _ and breakout on failureT, otherwise deleting the pattern space d.
sed 's/_/&/2;T;d' file
POSIX sed same as above but inverting the logic, ...
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5
votes
How to ignore all text containing special character more than once?
$ grep -v '_.*_' file
apple_ig
dog_ig
orange_ig
goat_ig
- 21.9k
0
votes
How to ignore all text containing special character more than once?
Using sed
$ sed -n '/^[^_]*_[[:alpha:]]\+$/p' input_file
apple_ig
dog_ig
orange_ig
goat_ig
- 1,092
3
votes
Accepted
How to ignore all text containing special character more than once?
With awk, to print only lines having maximum one underscore.
$ awk -F_ 'NF<=2' file
apple_ig
dog_ig
orange_ig
goat_ig
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6
votes
bash + how to compare arg to one of the disks in linux machine
Since lsblk allows for JSON output, it seems natural to use jq with it to figure out whether the given argument is a disk or not:
#!/bin/sh
if lsblk -J | jq -e --arg name "$1" '....
- 267k
1
vote
How to grep for specific format
Try this
grep '00+0530-..00+0530' myfile.txt
Dots (.) are inserted in the search string for any character. You do not need cat.
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2
votes
Accepted
How to grep for specific format
Assuming the substrings with four digits are timestamps, it appears you want to exclude the lines that contain timestamps from a quarter past the hour or quarter to the hour.
To do this, use grep like ...
- 267k
5
votes
bash + how to compare arg to one of the disks in linux machine
One possibility is to have two if-checks. At first, check if you can use $1 (the first argument) (it is not zero and is not --help) and then compare it to your lsblk-Output. For example:
#!/bin/env ...
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8
votes
Accepted
bash + how to compare arg to one of the disks in linux machine
You don't seem to be using most of the components of that command. All you need is:
lsblk -lnb | awk '$NF=="disk"{print $1}'
Then, to avoid the error message when no argument has been given,...
- 215k
3
votes
Count the number of words ends with specific character using Bash
elinks -no-numbering -no-references -dump https://matt.might.net/articles/what-cs-majors-should-know/ |
grep -Po '\w+s\b' |
wc -l
(with GNU grep or compatible)
Gives me: 595
elinks retrieves the ...
- 466k
0
votes
Grep and Cut command in linux
Using Raku (formerly known as Perl_6)
raku -ne '.put if .split(",")[8] >= 1;'
Sample Input:
ABC,XYZ,RTY,CREAM,FRANCE,170019,ST REMY CREME,3035540005229,0.75,1,15,26.99,10
ABC,RDS,...
- 1,098
1
vote
How can I add space after filename of grep output?
If all you need is a list of filenames containing text that matches a pattern, such as "zorro", and you intend to use those filenames with another program, then you can do something like the ...
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2
votes
Accepted
How can I add space after filename of grep output?
My first though went to awk
awk -F: -vOFS=: '{$1 = $1 " "; print}'
But that's doing more work than needed I think, splitting and re-joining the line.
The sed alternative is quite concise
...
- 78k
2
votes
sed or other equivalent for grep with vfF
Another way is to create dynamically the EREs, to start matching at the 225th position, with some help from sed, and grep for these EREs:
grep -vEf <(sed 's/.*/^.{224}&/' stem.txt) source.txt
...
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4
votes
Accepted
sed or other equivalent for grep with vfF
With awk, making sure you only look for those strings wherever they're meant to be.
awk '!source {stem[$0]; next}
! (substr($0, 225, 13) in stem)
' stem.txt source=1 source.txt > ...
- 466k
2
votes
Grep inserting file names from working directory
Try this example:
$ mkdir -p test_dir && cd test_dir/
$ touch file1 file2
$ time_trigger='<spec>H 1 * * *</spec>'
$ echo "$time_trigger"
<spec>H 1 * * *</spec&...
- 6,180
2
votes
Accepted
How to substact or sum 12 depending on the last and following line using awk?
Just keep a rolling buffer of 3 lines and examine that:
$ cat tst.awk
BEGIN { FS=OFS="," }
{
nxt = $0
prt()
}
END {
prt()
}
function prt() {
if ( cur ~ /Lumenal/ ) {
...
- 21.9k
2
votes
How to substact or sum 12 depending on the last and following line using awk?
I worked this one out before you changed the column separators to commas. First job was to change the multiple spaces to tabs in my test file:
$ cat indata
##sequence-region Q75T13 1 641
Q75T13 ...
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3
votes
How to substact or sum 12 depending on the last and following line using awk?
Try the following command:
root@u2004:~# cat test
##sequence-region Q75T13 1 641
Q75T13,UniProtKB,Chain,1,641,.,.,.,ID
Q75T13,UniProtKB,Topological domain,1,60,.,.,.,Note=Cytoplasmic
Q75T13,UniProtKB,...
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0
votes
Accepted
I'm trying to understand how to shorten regex
Well, [...] is a bracket group, it matches a single character that's any of the ones listed inside, obeying ranges (in some way that depends on the locale). [0-9\.] matches any digit from zero to nine,...
- 115k
-2
votes
How to extract rows in a file based on common information in another file?
You can easily achieve the result as:
while read FIRST
do
cat a.txt | grep "$FIRST" >> resut.txt
done < b.txt
let say your files are a.txt and b.txt and you want to get result in ...
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0
votes
Accepted
How to extract rows in a file based on common information in another file?
Key -f for grep is what you need.
$ grep -f file_with_patterns file_to_scan > result_file
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How to remember, which order grep and find takes the parameters?
grep and find I'm stumbling through, which order I should type the commands: When I should write the path and when I should write the flags, if it needs double quotations or not, etc. etc.
The ...
- 28.8k
1
vote
Accepted
Matching lines in file, with 2 lists of strings in order
Assuming you have GNU Awk available (for the FPAT internal variable), the following program should work:
awk 'BEGIN{FPAT="host ([[:digit:]]+.){3}[[:digit:]]+ [^ ]+"}
t=="src"{...
- 18.4k
2
votes
Accepted
how to grep the results (plural) of another command
If your shell offers "process substitution", try
command2 | grep -f <(command1)
If not, you can also pass the list of regexps on the command line using command substitution:
command2 | ...
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