First, a disclaimer: **[Please don't parse the output of `find`.](http://unix.stackexchange.com/q/321697/135943)**  The code below is for illustration only, of how to incorporate command substitution into an Awk script in such a way that the commands can act upon pieces of Awk's input.

To *actually* do a line count (`wc -l`) on each file found with `find` (which is the example use case), just use:

     find . -type f -name '*txt' -exec wc -l {} +

----

However, to answer your questions as asked:

##Q1
To answer your Q1:
 > Q1: is there a way to perform command substitution inside awk?

Of course there is a way, from `man awk` :

 > command | getline [var]
 >     Run command piping the output either into $0 or var, as above, and RT.

So ( Watch the quoting !! ):

    find . | awk '/txt$/{"wc -l <\"" $NF "\"|cut -f1" | getline(nl); print(nl)}'

Please note that the string built and therefore the command executed is 

    wc -l <file

To avoid the filename printing of `wc`.

Well, I avoided a needed file "close" for that command (safe for a couple of files, but technically incorrect). You actually need to do:

    find . | awk '/txt$/{
                           comm="wc -l <\"" $NF "\" | cut -f1"
                           comm | getline nl;
                           close (comm);
                           print nl 
                        }'

That works for older awk versions also.  
Remember to avoid the printing of a dot `.` with `find .`, that makes the code fail as a dot is a directory and wc can not use that. 

Or either, avoid the use of dot values:

    find . | awk '/txt$/ && $NF!="." {  comm="wc -l <\"" $NF "\" | cut -f1"
                                        comm | getline nl;
                                        close (comm);
                                        print nl 
                                     }'

You can convert that to a one-liner, but it will look quite ugly, Me thinks.

##Q2
As for your second question:

 > Q2: why is the first incantation above silently failing and is simply printing the filenames instead?

Because awk does not parse correctly shell commands. It understand the command as:

    nl = $(wc -l $NF)
    nl --> variable
    $ --> pointer to a field
    wc --> variable (that has zero value here)
    -  --> minus sign
    l  --> variable (that has a null string)
    $  --> Pointer to a field
    NF --> Last field

Then, `l $NF` becomes the concatenation of null and the **text** inside the las field (a name of a file). The expansion of such text as a numeric variable is the numeric value 0

For awk, it becomes:

    nl = $( wc -l $NF)
    nl = $ ( 0 - 0 )

Which becomes just `$0`, the whole line input, which is (for the simple find of above) only the file name.

So, all the above will only print the filename (well, technically, the whole line).