I'm using du to get the file size of the result archive in a packager script:
> du -smh archive.zip
51M archive.zip
I'd like to assign just the 51M part to a variable, to be able to print:
Archive size: 51M
How can I do that?
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3 Answers
You can do it like so:
$ variable=$(du -smh archive.zip | awk '{print $1}')
Details
awk will parse the output breaking it up into columns. You want just the results from column #1. The $( .. ) code will run a command and return its results.
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Works like a charm, thanks, for the explanation in particular!– BenMorelCommented Oct 6, 2013 at 16:51
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1@Benjamin if this answered your question, please mark it as accepted. That's the way to say thanks on the stack exchange sites.– terdon ♦Commented Oct 6, 2013 at 17:04
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@terdon I quite know that, but had to wait for 10 minutes before the system allowed me to accept the answer!– BenMorelCommented Oct 6, 2013 at 17:07
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@Benjamin Fair enough, sorry. I hadn't seen your profile and thought you were new to SE in general.– terdon ♦Commented Oct 6, 2013 at 17:11
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@terdon No worries, that's definitely annoying when people get their answer and walk away!– BenMorelCommented Oct 6, 2013 at 17:24
Or use the stat program, if it's available (usually on Linux by default). No human-readable K/M/G conversion, but it also doesn't require anything else to get just the number / has nice formatting options:
sauer@humpy:~$ stat -c "%s" /etc/passwd
2302
sauer@humpy:~$ stat -c "%n size: %s bytes" /etc/passwd /etc/shadow
/etc/passwd size: 2302 bytes
/etc/shadow size: 1389 bytes
Awk is a bigger hammer than you need, use a knife and cut,
variable=$(du -smh archive.zip | cut -f1 )
answered Oct 9, 2013 at 6:13
