Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems. It only takes a minute to sign up.
Sign up to join this community
I want when the computer start, a byobu session is started and a command executed in the first window (windows 0), without requiring any user intervention.
It is very important that this doesn't require an actual user to login.
How to do that?
I suppose this byobu will be accessible later to user root (or if possible another user ?)
If you want a command to be executed at boot time, you can put it in your crontab with @reboot instead of a time. So run crontab and add a line like
@reboot byobu -S boot-time mycommand
Instead of putting the command on the command line of byobu, you can put it in a Byobu session file.
If you want the session to be executed as root, you can start it from /etc/rc.local instead of root's crontab. Be sure to start it in the background, since the boot isn't complete until /etc/rc.local has finished running.
byobu -S boot-time mycommand &
Now byobu is based on tmux, the easiest way is to directly use tmux.
in my case I use the following syntax:
tmux new -d -s session-name /path/to/my/Script.sh
and connect to it I use:
tmux session has -t-name
in your crontab you will have to enter:
@reboot tmux new -d -s session-name /path/to/my/Script.sh
