I have a test running which crashes. I need to find out how far it reached before crashing. It will restart again after crashing and wipe the log file. This wiping takes 10 minutes though. So If I'm saving the log file every 9 minutes, I should be able to get the log file.
The problem is that how do I write a bash script to copy a log file to a specific location and overwrite an existing file (if any) only if the file being copied is larger than the file at the destination. Else I want to leave it alone.
25 if [ -f $testFile ]; then 26 COUNT=`cat $testFile|wc -l` 27 if [ $COUNT -gt 0 ];then 28 ARGS=`head -1 $testFile` 29 echo "Executing test for ARGS" 30 sed -i '1d' $testFile 31 cd /testCode; sleep 600
At this point, the code sleeps for 10 minutes, as mentioned
32 /testCode/startTest.sh $ARGS
This starts the test which removes the log file. If the test did not crash, then when the test is done it goes to the next command. Else it starts again from the top
33 `wall "System is going down for reboot in 600 seconds. Please save your work"` 34 sleep 600 35 /sbin/reboot & 36 exit 0 37 fi 38 fi
I figured out a way. So when the test starts, I save the logs from the previous run. Then I have enough time to check the logs while the test has restarted. The test usually crashes after an hour or so with segfaults. That gives me ample time to check the logs.
It is not a really clean way, but it will work. @Alexandre Alves also gave a good answer. That can work too. @Slm gave a good answer, but unfortunately that will not work in large tests like mine since that will clutter up the log file.
Also my issue is saving the log file, not logging per se.