Let's say I have files xinitrc, alphabetsoup, ieat.pie in the current directory. Need a bash script to select only xinitrc and alphabetsoup.
The bash extended glob
+([^.]) will match files without any . in their name. It requires that you have not unset
shopt extglob (on modern bash installations, it should be set by default). The pattern means:
any number (but at least one) of characters other than .
You can put all the filenames in an array:
NO_EXTENSION=( +([^.]) )
You can print the filenames:
printf "%s\n" +([^.])
Or pass them all to a utility:
ls -- +([^.])
If you want them in variable but not an array, you need to be very sure that no file has whitespace in its name. If you are absolutely certain of this, you can do:
The invocation of echo is necessary in order to get pathname expansion to happen, unlike in the array case. I strongly recommend using arrays for this sort of list, because you don't have to worry about special characters in the filenames.
You can get a list of files without full stop in their names in the working directory with:
find . -maxdepth 1 ! -name "*.*"
You can also have files which are
.file under unix, if you want to match those and
file, but not
file.ext then you can use:
find . -maxdepth 1 ! -name "*.*" -o -name ".*[^.]*"
extglob option, you can match the complement of a pattern, i.e. the files whose name do not match the pattern. Files with an extensions are the ones that match
*.*, so files with no extension in the current directory can be matched this way:
shopt -s extglob somecommand !(*.*)
Note that dot files (files whose name begins with
.) will not be included. If you want to match them as well and treat them as extensionless unless they contain a second
., you can use
shopt -s extglob nullglob somecommand !(*.*) .!(*.*)
shopt -s dotglob extglob somecommand !(?*.*)
Maybe you are looking for this:
$ ls | grep -v '\.'
$ ls alphabetsoup ieat.pie xinitrc $ ls | grep -v '\.' alphabetsoup xinitrc