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I need to recursively remove all files in all subdirs where the filename contains a number followed by an 'x' followed by a number, at least two times.
Example:
I'd want to remove these files:
'aaa-12x123-123x12.jpg'
'aaa-12x12-123x12-12x123.jpg'
But I do NOT want to remove these files:
'aaa.jpg'
'aaa-12x12.jpg'
'aaaxaaa-123x123.jpg'
'aaaxaaa-aaaxaaa.jpg'
How can I do that (from the bash shell)
A string contains “a number followed by an x followed by a number” if and only if it contains a digit followed by an x followed by a digit, i.e. if it contains a substring matching the pattern [0-9]x[0-9]. So you're looking to remove the files whose name matches the pattern *[0-9]x[0-9]*[0-9]x[0-9]*.jpg.
find /path/to/directory -type f -name '*[0-9]x[0-9]*[0-9]x[0-9]*.jpg' -delete
If your find doesn't have -delete, call rm to delete the files.
find /path/to/directory -type f -name '*[0-9]x[0-9]*[0-9]x[0-9]*.jpg' -exec rm {} +
-delete nor -exec rm worked for me in Bash on Windows. But this did: find /path/to/directory -type f -name '*[0-9]x[0-9]*[0-9]x[0-9]*.jpg' | xargs rm
-print0 and xargs -0, otherwise the command will fail with file names containing spaces or single quotes. But -delete and -exec rm do work on Windows. If something doesn't work, it's not due to their use.
Aug 13, 2015 at 9:50
find, so make sure the Unix utilities are first in PATH.
Aug 25, 2015 at 8:33
The right command is:
find . -type f -iregex '.*[0-9]x[0-9]*\.jpg$'
this will grab only files with names: 'aaa-12x12.jpg', but not 'aaa-12x12red.jpg'
