Bash script with input ipaddress file & csv file

Question

I have a bash script with an ipaddress.txt input file, that I want to use against a csv file. I want find the IP and then display the values of Column A (for now). I may want to display two or three columns. The script im using finds the IP but is not printing the value in Column A. To note: if it helps with the answer, IP address location is the 16th Column or Column P of csv file.

#!/bin/bash

# Read input file with IP addresses
input_file="ipaddress.txt"
while IFS= read -r ip_address; do
    # Search for IP address in CSV file
    csv_file="network-data.csv"
    grep -q "$ip_address" "$csv_file"

    # Print result
    if [ $? -eq 0 ]; then
        echo "$ip_address found in $csv_file"
        awk -F, -v "$ip_address"= '$16 == ip { print $1 }' "$csv_file"
    else
        echo "$ip_address not found in $csv_file"
    fi
done < "$input_file"

Here's a sample of the output

192.168.1.2 found in network-data.csv
awk: fatal: `192.168.1.2' is not a legal variable name
192.168.1.18 found in network-data.csv
awk: fatal: `192.168.1.18' is not a legal variable name
192.168.1.33 not found in network-data.csv
192.168.1.44 not found in network-data.csv
192.168.1.51 found in network-data.csv
awk: fatal: `192.168.1.51' is not a legal variable name

Answer 1

I used AWK instead of Bash. awk -f awkscript.awk ipaddresses.txt csvfile.csv

BEGIN {
    FS = ","; # Assuming CSV fields are separated by commas
}

# Load the IP addresses from file1 into an array
NR == FNR {
    ips[$0] = 1;
    next;
}

# Now we're working with the CSV file
{
    # The IP address is in the 16th field of the CSV
    if ($16 in ips) {
        print $1, $2; # Print columns 1 and 2
    }
}