I have to find some type of files in a directory and it's subdirectories and I only have to print out the filenames. So here's the main command:
find -type f -name "*.c"

Now, how could I cut the paths from each result? (it possibily could be done with awk, but I hope, that there's an easier way to do that).


GNU find supports the -printf predicate, which supports the %f format specifier for outputting on the filename.

find -type f -name "*.c" -printf '%f\n'
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  • answered so fast. tried out. thanks again ! :D – Adorjan May 20 '13 at 14:58

Using awk is not so complicated:

find . -name '*.c' -type f | awk -F/ '{print $NF}'

Or sed:

find . -name '*.c' -type f | sed 's|.*/||'

(assuming file names don't contain newline characters) and that will work with any find implementation.

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  • Assuming file names and path directory names don't contain newline characters. – Hauke Laging May 20 '13 at 15:40

You can use the basename program to get the file name:

find . -type f -name \*.c -exec basename {} +

This works on finds that don't have the GNU -printf extension.

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GNU find knows -printf. If you search subdirectories, too, then file names can occur multiple times (in general)!

You need -printf "%p\n" or -printf "%f\n".

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