Shell script to list all files in a folder on a single line

Question

I have this folder structure:

/Brand/ProductCode01
/Brand/ProductCode02

Each ProductCode## folder contains many JPG files, like

image01.jpg, image02.jpg and so on

I need to create a file that contains a single line for each ProductCode that lists all the files that exist in the folder "ProductCode##", like:

/Brand/ProductCode01/image01.jpg /Brand/ProductCode01/image02.jpg /Brand/ProductCode01/image03.jpg
/Brand/ProductCode02/image01.jpg /Brand/ProductCode02/image02.jpg

All the files need to be listed on a single line, separated by space and ended with newline at the last filename.

Any suggestions?

Thank You.

Answer 1

Don't confuse CR-LF and LF! AKA Carriage Return and Line Feed

Like this:

$ tree
.
└── Brand
    └── Ducati
        ├── A 1060
        │   ├── image01.jpg
        │   └── image02.jpg
        ├── A 1061
        │   ├── image01.jpg
        │   └── image02.jpg
        ├── A 1062
        │   ├── image01.jpg
        │   └── image02.jpg
        └── A 1063
            ├── image01.jpg
            └── image02.jpg

6 directories, 8 files

$ for d in ./Brand/Ducati/A*/; do echo "$d"image*.jpg; done | tee file.txt
./Brand/Ducati/A 1060/image01.jpg ./Brand/Ducati/A 1060/image02.jpg
./Brand/Ducati/A 1061/image01.jpg ./Brand/Ducati/A 1061/image02.jpg
./Brand/Ducati/A 1062/image01.jpg ./Brand/Ducati/A 1062/image02.jpg
./Brand/Ducati/A 1063/image01.jpg ./Brand/Ducati/A 1063/image02.jpg

Works both in bash and zsh and probably ksh and bourne like shells.

Answer 2

In zsh:

{
  for dir ( /Brand/ProductCode<->(Nn/) )
    () {print -rC1 -- "$*"} $dir/image<->.jpg(Nn)
} > your-file.txt

Or for directories (/ glob qualifier) with any names inside /Brand, and all regular files (. qualifier) within them recursively (still sorted numerically with the n glob qualifier):

{
  for dir ( /Brand/*(Nn/) )
    () {printf -rC1 -- "$*"} $dir/**/*(Nn.)
} > your-file.txt

Not that since newline (or space which you use as separator here) is as valid a character as any in a file paths, you could still get more than one line per brand.

Answer 3

It should work with

for i in /Brand/Ducati/*/; do ( find "$i" -type f | sed -e "s/^/'/" -e "s/$/'/"| tr '\n' ' '|sed "s/ $/\n/" ); done

• All file names (in the directory trees of /Brand/Ducati/subdirs/ ) will be listed (one set of lines for each subdir)
• a quote will be put before and after each file name (in order to manage file names with spaces and other special characters later on)
• newlines will be converted to spaces
• the last space in each line will be converted to newline

Answer 4

ls -1 | tr '\n' ' '

See also the -q and -b flags.