Exclude path from file name for 'find .' command

Question

I have a Master folder with following subfolders:

• f1
• f2

with jpeg/jpg files in each subfolder. I do find . -maxdepth 2 -type f -iname '*.jp*g' and getting output:

• ./f1/IM_48902.jpg
• ./f1/IM_48903.jpg
• ./f2/IM_48900.jpg
• ./f2/IM_48904.jpg

How I can exclude '/f1' and '/f2' from output and get such output?

• ./IM_48902.jpg
• ./IM_48903.jpg
• ./IM_48900.jpg
• ./IM_48904.jpg

[UPD] my full script is find . -maxdepth 2 -type f -iname '.jpg' ! -path "/excluded/" -print0 | xargs -I{} -0 -n1 -P3 sh -c 'exiv2 -q -K Xmp.dc.creator -K Xmp.photoshop.Credit -Pv "$1" > "/Users/adm/Desktop/$1.out"' -- {}

Answer 1

With GNU find, use the -printf action. See man find

find . -maxdepth 2 -type f -iname '*.jp*g' -printf "%f\n"

Answer 2

In general, you can run the output of find . -maxdepth 2 -type f -iname '*.jp*g' through e.g. sed:

% mkdir f1 f2; touch f1/abc f2/def
% find . -type f |sed -e 's:.*/:./:' 
./def
./abc

But if you need to do that for NUL-separated "lines", you need a sed that supports that, e.g. sed -z with GNU sed.

Alternatively, you could remove the prefix within the shell command later with the ${var##pattern} expansion which removes the longest matching prefix from the value.

$ find . -type f -print0 | xargs -I{} -0 sh -c 'echo "./${1##*/}"' -- {}
./def
./abc