6

I want to ls the files containing the substring "s1r", "s2r", "s3r" or "s19r" in their filenames.

I'm almost there!

Botched attempts:

ls *s[123][9?]r*

The above gives me only files including the substring

s19r

While

ls *s[1-3]|[19]r*

returns

-bash: [19]r*: command not found

ls: *s[1-3]: No such file or directory

That is, it does not recognize the or | operator - which makes sense as it is also used to pipe.

How do I ls the files containing "s1r", "s2r", "s3r" or "s19r"?

  • I'm on OS X if that matters. – The Unfun Cat Apr 24 '13 at 7:21
  • 1
    ls *s@([123]|19)r*? – manatwork Apr 24 '13 at 7:23
  • ls s@([123]|19)r gives '-bash: syntax error near unexpected token `('' – The Unfun Cat Apr 24 '13 at 7:24
  • Which bash version? Are you trying in interactive or non-interactive shell session? pastebin.com/VSSTt6qC – manatwork Apr 24 '13 at 7:29
  • 1
    @TheUnfunCat You need to enable the cool stuff with shopt -s extglob – Hauke Laging Apr 24 '13 at 7:37
5

Use ls *s1r* *s2r* *s3r* *s19r*.

If you care about non existing files you can set the nullglob option:

          nullglob
                  If  set,  bash allows patterns which match no files (see
                  Pathname Expansion above) to expand to  a  null  string,
                  rather than themselves.

If your shell is not bash, there is probably a similar way. Have a look at it's man page.

1

You might want to try this:

ls *s?([123])r* *s19r*

For example

I have a directory with the following files:

% ls | column
s10r    s12r    s14r    s16r    s18r    s1r s2r s4r s6r s8r
s11r    s13r    s15r    s17r    s19r    s23r    s3r s5r s7r s9r

Using the above mentioned ls:

% ls *s?([123])r* *s19r*
s19r  s1r  s2r  s3r

See the bash manual on pattern matching for more details.

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