Do not list parent directory as part of subdirectories when using find

Question

Suppose I have this going:

$ find ./src -name '*.txt'
./src/file1.txt
./src/subdir1/file2.txt
./src/subdir1/subsubdir1/file3.txt
./src/subdir2/file4.txt

I want to exclude the directory being searched, so something like:

./file1.txt instead of ./src/file1.txt
./subdir1/file2.txt instead of ./src/subdir1/file2.txt and so on.

Adding -mindepth 1 didn't do anything.

Is it possible to do what I'm after purely in find?

Answer 1

For situations where you don't have a version of find that supports -printf '%P' you can use this alternative structure to avoid including the search path.

Starting point as in the question:

find ./src -name '*.txt'

Same but without the search path in the results

( cd ./src && find . -name '*.txt' )

Assuming the file structure shown in your question, the result is

./file1.txt
./subdir1/file2.txt
./subdir1/subsubdir1/file3.txt
./subdir2/file4.txt

Answer 2

Expanding on what @steeldriver said:

$ cd "$(mktemp --directory)" # create temporary directory
direnv: unloading
$ mkdir foo bar
$ touch foo/1 bar/2
$ find foo bar -type f -name '*' -printf '%P\n'
1
2

The %P formatting string is documented as follows by the GNU find manual:

%P
File's name with the name of the starting-point under which it was found removed.

Here, "file's name" means the pathname of the found file, not just the filename.