I am very new to using at and am wondering how to display the command by a scheduled job.
postgres@dcjsn-jv2526:/opt/db/backup/postgres/dumps> atq
29 Wed Nov 2 18:55:00 2022 a postgres
I see there is a job 29 scheduled for a certain time by a certain user. Now I want to examine the command to be executed. How do I achieve that? There is nothing on this in the manpage.
The command
at -c 29
should do it. Note that the job file includes your full environment, so scroll down to the bottom if necessary to see the script that is executed.
The at(1) man page says:
-c cats the jobs listed on the command line to standard output.
You need to be superuser to examine jobs of other users though.
It can also be done in this way
┌──[[email protected]]-[/var/spool/at]
└─$ls /var/spool/at/
a0000101a80dd0 a0000201a80dd0 spool
┌──[[email protected]]-[/var/spool/at]
└─$cat a0000201a80dd0
at job?
ls of /var/spool/at I believe. OTOH, at -c 29 will work as long as you are the owner of the job. I also tried to cat the file directly and I still get permission denied even though I own it: the directory perms don't allow it. So even if you can guess the filename, you won't be able to see it unless you are the superuser.