How to print different fields from different lines with AWK

Question

Here is my sample :
PING my.host.local (10.10.10.10): 56 data bytes
64 bytes from 10.10.10.10: icmp_seq=0 ttl=63 time=2.034 ms

--- my.host.local ping statistics ---
1 packets transmitted, 1 packets received, 0.0% packet loss
round-trip min/avg/max/stddev = 2.034/2.034/2.034/0.000 ms

I would like to do something like : if /64 bytes/ then print something like : "'my.host.local' is up"

The problem is when I do a regex of /64 bytes/ then I'm losing the line showing the host name "my.host.local" and therefore I can't use that field to print my final message.

how would you do this ?

Cheers,

Answer 1

Use a variable to store the host name:

awk '/^PING/ { host = $2 } /^64 bytes/ { print host " is up" }'

To do something if the host is down, you need to note if a response was seen, and handle both cases at the end:

awk '/^PING/ { host = $2 }
     /^64 bytes/ { up = 1 }
     END {
       if (up) { print host " is up" }
       else { print host " is down" }
     }'

Answer 2

You could do something like

ping -c 1 $machine | awk '
  $1 == "PING" {host = $2}
  $2 == "bytes" {
    if ($1 == 64)
      print host " is up"
    else
      print host " did not ping 64 bytes"
  }
'

Answer 3

You presumably know the host already (because you used it to run ping) and detecting the 64 bytes text is not necessary since you can use the exit status of ping:

myhost=my.host.local

if ping -c 1 -t 5 "$myhost" >/dev/null 2>&1
then
    printf 'host %s is up\n' "$myhost"
else
    printf 'host %s does not appear to be reachable\n' "$myhost"
fi

This tries to ping the given host with a timeout. It throws away any output because only the exit status of the utility is interesting. This is used by if to decide which branch to take.

On FreeBSD, -t sets the timeout in seconds. On Linux, -t sets the TTL, and ping waits for twice as many seconds.