I've compiled Linux kernel 5.18.4 from source, enabling all the EFI-related options, without any built-in parameters, nor a default init path, also, it's worth mentioning that i'm not making use of initramfs/initrd

I'm trying to boot this kernel through VirtualBox 6.1.34, on a VM with EFI support

The installation disk (/dev/sda) has two partitions:

  • /dev/sda1 a 512mb EFI system partition formatted as FAT32 mounted at /boot
  • /dev/sda2 a 15.5gb root partition formatted as ext4 mounted at /

The kernel is located at /boot/EFI/BOOT/boox64.efi, seems like this naming convention makes it boot automatically, skipping the UEFI shell, and removing the need for creating a boot entry through efibootmgr, but i'm not sure if that's the norm across different UEFI implementations on different hardware

Whenever i try to boot it, i get the following error:

virtualbox uefi error

On previous attempts, by making minor adjustments like changing the kernel path and doing some other tweaks, the result was similar, whenever i tried to execute vmlinuz.efi through the EFI shell, the machine would hang forever, without displaying a single error message (this is the case even when passing root=/dev/sda2 and init=/bin/init as parameters)

1 Answer 1


I had to enable framebuffer on kernel .config in order to prevent running into a blank screen:


Thanks to d9ngle for his answer

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