I am doing a "deep search" within several pdf files with "pdfgrep", trying to find a word and get a count on the documents like this:

# pdfgrep -ric PATTERN


Any idea how i can ignore the printout for files with an defined number of counts? Like 0 or less than...?

1 Answer 1


Assuming file paths don't contain newline characters, you can just pipe that output to:

grep -v ':0$'

To filter out the lines ending in :0.


awk -F: '$NF >= 10'

To only list the files with at least 10 matches.

To handle arbitrary file paths including those with newline characters, use NUL delimiters:

pcregrep -ricZ pattern | gawk -v RS='\0' '
  {RS="\n"; getline count; RS="\0"}
  count > 0 {print $0":"count}'
  • Thanks a lot! :)
    – Nils
    May 27, 2022 at 8:25

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