Get argument position given its value in a bash script

Question

How can I get the position of an argument by using its value?

For example:

myScript.sh hello world

echo "$1"
hello

How can I get the position of 'hello', which is 1 in this case?

Answer 1

While it wouldn't surprise me if there were quicker, easier ways, something like this should work:

#!/bin/bash
pos=0
found=no
for arg ; do
    let pos++
    if [[ "$arg" == "hello" ]] ; then
        found=yes
        break
    fi
done
if [[ "$found" == "yes" ]] ; then
    echo "Found hello at position $pos"
else
    echo "hello not found"
fi