How to get the time of several commands with a loop

Question

I have this command:

time -p sh -c 'command1; command2;'

So command1and command2 is executed and I get the real, user and sys time printed on the console.

But I want that command1; command2; is looped 10 times and then I want to get the time which is used for the two commands.

Stéphane Chazelas · Accepted Answer · 2013-03-24 19:34:41Z

23

With zsh:

time (repeat 10 {cmd1; cmd2})

zsh's repeat is inherited from csh.

With tcsh:

time repeat 10 eval 'cmd1; cmd2'

Would give you the time for each iteration and the overall time at the end.

answered Mar 24, 2013 at 19:34

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Bernhard · Accepted Answer · 2013-03-24 18:38:38Z

18

You can write a simple for-loop

 time -p bash -c "for (( i=0; i<10; i++ )); do command1; command2; done;"

Note that I used bash instead of sh for the loop.

answered Mar 24, 2013 at 18:38

Bernhard

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21

In bash you can just time (for i in {1..10}; do sleep 1 ; done)
– frostschutz
Mar 24, 2013 at 18:47
2

@frostschutz: Yours seems like a much better answer. Please post it as an answer.
– Chris Page
Jan 24, 2016 at 21:58
anyway to do this for multiline forloop?
– Brian Wiley
Dec 10, 2020 at 15:14

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qwr · Accepted Answer · 2020-05-29 23:46:28Z

5

For simple for loops you can time the for loop directly:

time for i in {1..10}; do echo $i; sleep 1; done

answered May 29, 2020 at 23:46

qwr

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3 Answers 3