How to get the time of several commands with a loop

Question

I have this command:

time -p sh -c 'command1; command2;'

So command1and command2 is executed and I get the real, user and sys time printed on the console.

But I want that command1; command2; is looped 10 times and then I want to get the time which is used for the two commands.

Bernhard · Accepted Answer · 2013-03-24 18:38:38Z

13

You can write a simple for-loop

 time -p bash -c "for (( i=0; i<10; i++ )); do command1; command2; done;"

Note that I used bash instead of sh for the loop.

answered Mar 24 '13 at 18:38

Bernhard

10.1k3 gold badges51 silver badges69 bronze badges

14

In bash you can just time (for i in {1..10}; do sleep 1 ; done) – frostschutz Mar 24 '13 at 18:47
1

@frostschutz: Yours seems like a much better answer. Please post it as an answer. – Chris Page Jan 24 '16 at 21:58

add a comment |

Stéphane Chazelas · Accepted Answer · 2013-03-24 19:34:41Z

16

With zsh:

time (repeat 10 {cmd1; cmd2})

zsh's repeat is inherited from csh.

With tcsh:

time repeat 10 eval 'cmd1; cmd2'

Would give you the time for each iteration and the overall time at the end.

answered Mar 24 '13 at 19:34

397k71 gold badges783 silver badges1192 bronze badges

add a comment |

qwr · Accepted Answer · 2020-05-29 23:46:28Z

1

For simple for loops you can time the for loop directly:

time for i in {1..10}; do echo $i; sleep 1; done

answered May 29 at 23:46

qwr

3312 silver badges10 bronze badges

add a comment |

3 Answers 3