I have the following file from which I want to extract only Removed '2022-01-30_01-00-05', at the end.

Removing '2022-01-30_01-00-05'...
  0.46% complete (00:03:45 remaining)^M  5.49% complete (00:00:17 remaining)^M 24.90% complete (00:00:06 remaining)^M 60.56% complete (00:00:01 remaining)^M 82.12% complete (00:00:00 remaining)^M 82.39% complete (00:00:01 remaining)^M 84.24% complete (00:00:01 remaining)^M 86.48% complete (00:00:01 remaining)^M 88.58% complete (00:00:01 remaining)^M 89.66% complete (00:00:01 remaining)^M101.08% complete (00:00:00 remaining)^M104.62% complete (00:00:00 remaining)^M                                                                                ^MRemoved '2022-01-30_01-00-05'

I've tried dos2unix but it didn't work.

I've tried these variations, below, but when I less output they either don't remove the ^M characters, or the whole line is captured:

tr -d $'\r' < /file | grep "Removed" > output
tr -d '^M' < /file | grep "Removed" > output
tr -d ^M < /file | grep "Removed" > output
sed 's/\r//g' < /file | grep "Removed" > output

4 Answers 4


The grep command will print the entire matching line and since lines in *nix are defined by \n and not \r, what you describe is normal behavior. In other words, your first and last commands (the tr -d '\r' and the sed 's/\r//g') are both working as intended, it's just that grep is doing what it's supposed to do and printing the entire line.

To only print part of a line, you need GNU grep and its -o option. For example:

$ grep -oP "Removed\s*'[^']+'" file
Removed '2022-01-30_01-00-05'

Alternatively, change the \r (the ^M) to newline characters instead of deleting them:

$ tr '\r' '\n' < file | grep Removed
Removed '2022-01-30_01-00-05'


$ sed 's/\r/\n/g' file | grep Removed
Removed '2022-01-30_01-00-05'
  • Also tr '\r' '\n' <file | tail -n 1, or tail -n 1 file | sed 's/.*\r//'.
    – they
    Feb 6 at 7:14

dos2unix strips control-Ms (\r) from immediately before the end of lines (\n) - that's not what you have, you have control-Ms instead of end of lines. Hence dos2unix not helping you.

With GNU awk for multi-chars RS and using any sequence of \rs and/or \ns as the record separators:

$ awk -v RS='[\r\n]+' '/^Removed/' file
Removed '2022-01-30_01-00-05'
awk '{for(i=1;i<=NF;i++){if($i ~ /Removed/){print $i,$(i+1)}}}' filename| awk '{gsub(/\^M/,"",$0);print }'


Removed '2022-01-30_01-00-05'

Your input file has Mac line breaks. You can convert them to Unix line breaks with

dos2unix -c mac file


mac2unix file

To find out which type of line breaks your file has you can use this command:

dos2unix -ih file

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