How to get number in the first line of a file

Question

My input files are file_1.txt, file_2.txt, file_3.txt and so on. These files contains data such as

$ head file_*.txt
==> file_1.txt <==
----- Reset Loop 1 -------

Test #1
data

Test #2
data

Test #3

Test #4
data

==> file_2.txt <==
----- Reset Loop 2 -------

Test #1

Test #2
data

Test #3

Test #4
data


==> file_3.txt <==
----- Reset Loop 3 -------

Test #1
data

Test #2
data

Test #3

Test #4

The code I have right now to get filename and the sequence number behind Test only if the data available under each Test from the input file is:

#!/bin/bash

awk '
    FNR==1 {
        testId = ""
        split(FILENAME,f,/[_.]/)
        fileId = f[4]
    }
    testId != "" {
        if (NF) {
            print testId > "1_val.txt"
            print fileId > "2_val.txt"
        }
        testId = ""
    }
    sub(/^Test #/,"") {
        testId = $0
    }
' file_*.txt

The output i get from this code:

1_val.txt

1
2
4
2
4
1
2

2_val.txt

਱਱਱਱਱਱਱਱਱਱ਲਲਲਲਲਲਲਲਲਲਲ਼ਲ਼ਲ਼ਲ਼ਲ਼ਲ਼ਲ਼ਲ਼ਲ਼ਲ਼਴਴਴਴਴਴਴਴਴਴ਵਵਵਵਵਵਵਵਵਵ

There might be some problem in my OS or something else as there are weird characters in my output file. I have thought of an alternative of getting the number in the first line of the input file for the data listed in 1_val.txt.

The code I have for this is awk 'NR==1' file_*.txt but I am not so sure where to insert this particular command in the script.

The expected output:

2_val.txt

1
1
1
2
2
3
3

Edit: This is the exact command I am running to create the output files.

thulasyc > cat data_collect.sh
#!/usr/bin/env bash

awk '
    FNR==1 {
        testId = ""
        fileId = $4
    }
    testId != "" {
        if (NF) {
            print testId > "1_val.txt"
            print fileId > "2_val.txt"
        }
        testId = ""
    }
    sub(/^TX PTP Command #/,"") {
        testId = $0
    }
' "${@:--}"
thulasyc > ./data_collect.sh ptp_log_reset_*.txt
thulasyc > head *_val*
==> 1_val.txt <==
1 
2 
3 
5 
6 
11 
12 
13 
15 
16 

==> 2_val.txt <==
1
1
1
1
1
1
1
1
1
1

The display of the content of the output files:

1_val.txt

2_val.txt

Answer 1

$ cat tst.sh
#!/usr/bin/env bash

awk '
    FNR==1 {
        testId = ""
        fileId = $4
    }
    testId != "" {
        if (NF) {
            print testId > "1_val.txt"
            print fileId > "2_val.txt"
        }
        testId = ""
    }
    sub(/^Test #/,"") {
        testId = $0
    }
' "${@:--}"

$ ./tst.sh file_*.txt

$ head *_val*
==> 1_val.txt <==
1
2
4
2
4
1
2

==> 2_val.txt <==
1
1
1
2
2
3
3

Answer 2

Do you have to use awk? To do it in perl you could start with something like:

#!/usr/bin/perl

use strict;
use warnings;
use diagnostics;

#put your files here:
my @files = ('file_1.txt','file_2.txt');

foreach my $filename (@files) {
    my $test;
    my $number;
  open(my $fh, "<", $filename)
    or die "Can't open $filename ";
        print "$filename:\n";
        while(my $row = <$fh>) {
            if ($row =~ /^Test #.*/){
                $test = 1;
                $number = $row;
                $number =~ s/\D//g;
            }
            elsif ($test and (length($row) > 1) ) {
                print "$number\n";
                $test = 0;  
            }
        }
        close $fh;
}

Edit: Also your question says ' first line of a file ', however the data you posted seems to imply the files contain more than one test so this code takes that into account.