I have the following grep
grep "/abc/[A-Z]" file1.txt | cut -d/ f3 | sort -u
The grep worked perfectly returning the results,
ALPHA
abc
BRAVO
CHARLIE
However, why is the abc in the output too? I have made the regex to only take capitalize words after the delimiter backslash. Is this an intended output and how should I remove the abc from the output?
You have not anchored the regular expression that you use with grep. A consequence of this is that it may match anywhere on the line.
A line saying, e.g.,
blah/blah/abc/Abc
or
/blah/abc/Abc
would match your expression, and both would contain the string abc as the 3rd /-delimited field.
To anchor your expression to the start of the line, use
^/abc/[A-Z]
Alternatively, enforce a more strict match some other way, or weed out the abc result at the end using grep -v -F -x abc, whichever method suits your style and application the best.
grep -oprints the matching part only. Which would be e.g./abc/Ahere, not/abc/ALPHA.abc, then you'll need to add sample text to your question so that we have an idea of what you are working with.cut f3reads a file calledf3. You probably usedcut -f3. Also, if you want the whole name to be uppercase, you need a repeat on the character range, and a terminator, like[A-Z]+$: your pattern only examines the first character of the field.