Bash variable with curl

Question

When I run the following, it works and returns one item.

curl -X POST -d 'tag=jazz' -d 'state=queensland' http://all.api.radio-browser.info/json/stations/search

But in a Bash script, when I use -d 'tag=jazz' -d 'state=queensland' for RES, I get different outputs.

read -rp "Write your quiry " RES
    echo "$RES"
    curl -X POST "$RES" http://all.api.radio-browser.info/json/stations/search

I tried this but it didn't work.

curl -X POST http://all.api.radio-browser.info/json/stations/search <<EOF
    "$RES"
EOF

How can I use a variable in a Bash script?

The "$RES" will be sent to curl as one argument, not four. — ibuprofen, Jul 7, 2021 at 2:50

Freddy · Accepted Answer · 2021-07-07 02:10:22Z

1

Use an array as in the answer to your previous question:

read -rp 'Write your query ' -a RES
curl -X POST "${RES[@]}" http://all.api.radio-browser.info/json/stations/search

Enter your arguments without single quotes since they are saved literally into the array, i.e. use

-d tag=jazz -d state=queensland

answered Jul 7, 2021 at 2:10

Freddy

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