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What's the easiest way to show memory usage of processes with the same name?

Not individually, but the total usage.

To figure out how much things like Chrome consume memory.

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I would select all the process with pgrep, print resident memory with ps and sum it using awk:

ps -p $(pgrep -d, -x chrome) -ho rss | awk '{s+=$1} END {printf "%i", s}'

For some process it's probably better to look for full command line instead of name. On my distribution, using chromium:

ps -p $(pgrep -d, --full /usr/lib/chromium/chromium) -ho rss | awk '{s+=$1} END {printf "%i", s}'
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  • running this command gives me error: only one heading option may be specified(from ps). I'm on Gentoo – Hrisip Feb 20 at 18:06
  • Hum, maybe try --no-headers -o rss instead? – kaliko Feb 20 at 19:31
  • ps -p $(pgrep -d, -x chrome) --no-headers -o rss | awk '{s+=$1} END {printf "%i", s}' same. – Hrisip Feb 20 at 19:41
  • Damned, I guess we have different ps implementations or version. What about: ps -p $(pgrep -d, -x chrome) -o rss | awk '$1 ~ /^[0-9]+$/ {s+=$1} END {printf "%i", s}' ? – kaliko Feb 20 at 19:51
  • nah. I guess the problem is that the pgrep command gives output in the following form 3402 chrome,3410 chrome – Hrisip Feb 20 at 19:55

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