What's the easiest way to show memory usage of processes with the same name?
Not individually, but the total usage.
To figure out how much things like Chrome consume memory.
I would select all the process with pgrep, print resident memory with ps and sum it using awk:
ps -p $(pgrep -d, -x chrome) -ho rss | awk '{s+=$1} END {printf "%i", s}'
For some process it's probably better to look for full command line instead of name. On my distribution, using chromium:
ps -p $(pgrep -d, --full /usr/lib/chromium/chromium) -ho rss | awk '{s+=$1} END {printf "%i", s}'
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running this command gives me
error: only one heading option may be specified(from ps). I'm on Gentoo – Hrisip Feb 20 at 18:06 -
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ps -p $(pgrep -d, -x chrome) --no-headers -o rss | awk '{s+=$1} END {printf "%i", s}'same. – Hrisip Feb 20 at 19:41 -
Damned, I guess we have different ps implementations or version. What about:
ps -p $(pgrep -d, -x chrome) -o rss | awk '$1 ~ /^[0-9]+$/ {s+=$1} END {printf "%i", s}'? – kaliko Feb 20 at 19:51 -
nah. I guess the problem is that the
pgrepcommand gives output in the following form3402 chrome,3410 chrome– Hrisip Feb 20 at 19:55
