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I am doing this script (with zsh, but I guess that it is not very important):
mylist=`seq 1 3`
for i in $mylist ; do echo "abc/$i" ; done
This gives :
abc/1
2
3
while I would like to see :
abc/1
abc/2
abc/3
A huge thanks to somebody that may find why it does not work/how to do.
You can keep it simple:
for i in 1 2 3; do echo "abc/$i" ; done
OR
for i in $(seq 1 3); echo "abc/$i"
Output:
abc/1
abc/2
abc/3
Another way to do this kinda thing is via brace expansion:
echo abc/{1..3}
But naturally, since you asked for newlines, you'd need to do it like this:
abc_strings=( abc/{1..3} )
printf "%s\n" "${abc_strings[@]}"
Just tried this in an online Zsh :
for i in `seq 1 3`
do
echo "abc/$i\n"
done
Got the following:
abc/1
abc/2
abc/3
seq 1 3 for i in $mylist ; do echo "abc/$i" ; done This gives : abc/1 2 3
Jan 10, 2021 at 20:44
mylist=( $(seq 1 3) )(you can use backticks in place of$(...)for the command substitution if you prefer, however it is considered deprecated)#! /bin/shat the top of the file. Depending on your system this may run ksh/zsh/bash/dash/ash, but in any case in a mode that disables such features as the one which is causing this behavior. N.B. on most systems /bin/sh is not completely POSIX compatible, but usually good enough.$mylistto${=mylist}. That enables word splitting on the variable expansion.