I would like to replace every occurrence of *text* into {\i text}.
text *text* text
*text* text *text*
*text text text* text
should become
text {\i text} text
{\i text} text {\i text}
{\i text text text} text
etc.
How can I do this?
Add a comment
|
2 Answers
Assuming that each occurrence of *some text* is on a single line (ie. not split across multiple lines):
sed -r 's/\*([^*]+)\*/{\\i \1}/g' file
-
looks nice, just one \ missed (perhaps through autoformatting): sed -r 's/*([^*]+)*/{\\\i \1}/g' file– InnoJan 25, 2013 at 14:44
-
I did it this way in three steps: sed -e "s/^*/{\\\i /g" -e "s/ */ {\\\i /g" -e "s/*/}/g" file– InnoJan 25, 2013 at 14:45
-
It may depend on which
sedyou use. I get the same output with\\\ias with\\i. I am using `GNU sed version 4.2.1'– Peter.OJan 25, 2013 at 14:47 -
Note that the syntax is GNU specific, so would have to be adapted when ported to a non-GNU system. Jan 25, 2013 at 14:48
-
With any POSIX sed, and if the *...* may span multiple lines, you could do:
sed -e :1 -e 's/\*\([^*]\{1,\}\)\*/{\\i \1}/g;/\*/!b' -e '$q;N;b1'
Note that some sed implementations have a relatively low limit on the size of their pattern space, so those may fail if the *...* span too many (long) lines.
With perl:
perl -0777 -pe 's/\*(.*?)\*/{\\i $1}/gs'
But beware that it slurps the whole file in memory prior to doing the substitutions which could be a problem for huge files. Also note that perl has a -i option to update the file in place (which some sed implementations have borrowed)
answered Jan 25, 2013 at 14:46
