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I tried the below command to search for in all files user /var

sudo find . -type f | xargs sudo grep 202007602 | tee /tmp/202007602.log

Output:

grep: ./www/html/jenkins/workspace/node_modules/xpath/docs/xpath: No such file or directory
grep: methods.md: No such file or directory
grep: ./www/html/jenkins/workspace/Efendibey-Live/node_modules/xpath/docs/function: No such file or directory
grep: resolvers.md: No such file or directory
sudo: unable to execute /bin/grep: Argument list too long
sudo: unable to execute /bin/grep: Argument list too long

Then, I tried a solution from stackoverflow but that too does not work and i get the below error:

sudo find /var -type f -exec sudo grep -l '202007602' {} + | tee /tmp/202007602.log
sudo: unable to execute /bin/grep: Argument list too long
sudo: unable to execute /bin/grep: Argument list too long
....
....

I'm using centos 7.

Can you please suggest ?

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  • 1
    Why do you use sudo both on the find and on the grep? It should be enough to have find run with sudo. Drop the sudo from -exec sudo grep. Does that solve it?
    – Kusalananda ♦
    Sep 13, 2020 at 6:14
  • In your first attempt, filenames are obviously being split. You need to use -print0 in find, and -0 in xargs, to fix this. In your second attempt, -exec requires a ";" to terminate the enclosed command.
    – Paul_Pedant
    Sep 13, 2020 at 10:07

1 Answer 1

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0

Let GNU grep do the work for you with its -r flag

sudo grep -r 202007602 /var | tee /tmp/202007602.log
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