I'm new to Unix scripting, so please bear with me.
I am given a file which has information on processes on each line. I need to extract certain information on these processes from each line.
Example of the file -
process1 port=1234 appID=dummyAppId1 authenticate=true <some more params> process3 port=1244 authenticate=false appID=dummyAppId2 <some more params> process2 appID=dummyAppId3 port=1235 authenticate=true <some more params>
The desired output is -
1 port=1234 authenticate=true appID=dummyAppId1 2 port=1244 authenticate=false appID=dummyAppId2 3 port=1235 authenticate=true appID=dummyAppId3
The numbers 1, 2, and 3 on each line just denote the line number of the output file.
I have already tried using the
s/ command but it is order-specific, while the parameters in the input file don't follow an order - as a result, some lines in the input file are skipped.
Here is my command -
sed -nr 'appId/s/(\w+).*port=([^ ]+) .*authenticate=[^ ]+) .*appId=[^ ]+) .*/\2\t\3\t\4/p' | sed =
Could anyone guide me on how to extract those parameters regardless of order?
Edit 1: I managed to use grep's look-behind zero-width assertion feature this way -
grep -Po '(?<=pattern1=)[^ ,]+|(?<=pattern2=)[^ ,]+|(?<=pattern3=)[^ ,]+|(?<=pattern4=)[^ ,]+' filename
but this seems to give the output for each line in new lines i.e.
1234 true dummyAppId1
Trying to figure out how to get it on one line using grep (i.e. not via merging X lines into 1)
Edit 2: mixed-up the order of parameters in the input
Edit 3: I'm sorry, I should have mentioned this earlier -
perl seems to be restricted on the machines I work on. While the answers provided by Stephane and Sundeep work perfectly when I test it out locally, it wouldn't work on the machines I need it to finally run on.
It looks like awk, grep, and sed are the mainly supported options :(