how to use grep for specific files?

Question

for example I type

ls -altr | grep "23 Dec"

so it will show files for 23 Dec only and I want to use grep for them, like

ls -altr | grep "23 Dec" | xargs grep -l "some_string"

but this doesn't work)

How to do that?

Answer 1

If you want to use your way, try maybe:

ls -altr | grep "23 Dec" | awk '{print $9}' | xargs -i grep -l "some_string" {}

or with find I would do:

find . -type f -newermt 2012-12-23 ! -newermt 2012-12-24 -exec grep -l "some_string" {} \;

In the find command, don't forget the escaped semicolon. Also note that find works much the same way as xargs when used with the -exec option.

Answer 2

If you were trying to find some files, that was modified on a specific date,

there would be no need for pipe, (ls uses modify time by default)

find . -type f -newermt 2012-12-23 ! -newermt 2012-12-24 -iname '*some_string*'