27

I would like to add text to the end of filename but before the extension. Right now I am trying,

for f in *.shp; do echo $f_poly; done

the output is,

Quercus_acutifolia.shp_poly
Quercus_agrifolia.shp_poly
Quercus_corrugata.shp_poly
Quercus_cortesii.shp_poly
Quercus_costaricensis.shp_poly
Quercus_havardii.shp_poly
Quercus_hemisphaerica.shp_poly
Quercus_kelloggii.shp_poly
Quercus_knoblochii.shp_poly
Quercus_laceyi.shp_poly

I want it to be,

Quercus_acutifolia_poly.shp
Quercus_agrifolia_poly.shp
Quercus_corrugata_poly.shp
Quercus_cortesii_poly.shp
Quercus_costaricensis_poly.shp
Quercus_havardii_poly.shp
Quercus_hemisphaerica_poly.shp
Quercus_kelloggii_poly.shp
Quercus_knoblochii_poly.shp
Quercus_laceyi_poly.shp
28

Using standard POSIX parameter expansion:

for f in *.shp; do printf '%s\n' "${f%.shp}_poly.shp"; done
  • Awesome that is exactly what I needed. – Sam007 Nov 26 '12 at 21:05
  • 1
    Might be better with an explanation how it works. The Doug answer is pretty easy, on the other hand. – Display Name Jun 23 '15 at 12:41
  • @SargeBorsch What do you need explained? My answer, the snippet in the question, and Doug's answer are only differ by a few characters, and Doug's answer explains even less than mine so I don't know what it is you want. If you just compare the difference in the two outputs in the question it should be trivially easy to figure out what they do. I can explain why my answer is preferable to Doug's. 1. I use printf with a format string instead of the less portable echo. 2. I use parameter expansion which is more efficient than calling an external binary (basename) for such a simple task. – jw013 Jun 23 '15 at 14:43
  • Then the command to rename the files would be this: for f in *.shp; do mv $f ${f%.shp}_poly.shp; done – Patch92 Feb 13 '19 at 12:28
6

Sometimes there is a tool called "rename" installed.

rename 's/\.shp$/_poly.shp/' *shp

It might not be portable but it is easy to use.

  • 1
    This is the only one that worked for me, great answer! – wanderer0810 Dec 22 '17 at 6:57
5

Use this:

for file in *.shp; do echo $(basename $file .shp)_poly.shp; done
  • 3
    Using basename is slower and less efficient than letting the shell do the work by itself. This may be noticeable for very large numbers of files. – jw013 Nov 26 '12 at 21:14
  • Also, there are missing quotes and --s and it fails for filenames that have newline characters before the .shp. – Stéphane Chazelas Nov 16 '16 at 22:57
  • Thanks for giving an answer I can actually work with for my purpose. This is bash help, not code golf. (reading over this.. I realize it may have sounded like I was being sarcastic. More gripping about the other answers on here than yours. Thanks again) – Tim Jul 4 '19 at 15:48
3

This worked better for me:

for f in *; do NEW=${f%.webm}_2016.webm; mv ${f} "${NEW}"; done

  • Well this looks a lot like the accepted answer except that you probably want for f in *.webm, you forgot to quote the ${f} and you're missing a --. – Stéphane Chazelas Nov 16 '16 at 22:45
  • 1
    The accepted answer doesnt work on OSX, it only prints out the new file names, it doesnt actually rename the files – Vinnie James Nov 16 '16 at 22:47
  • 1
    Of course, it shows you how to use shell expansions to get the new file name, in response to the question that is also outputing a file name (with echo), but not the required one. – Stéphane Chazelas Nov 16 '16 at 22:54
1

If they are in different locations then run :-

for i in ` find /root/test/ -name "*.shp" ` ;
do
  mv $i ` echo $i | sed 's/.shp$/_poly.shp/g' ` ;
done
1

As the question is for bash there is no need for external utilities, since you can use bash regexps:

for i in *.shp
do
    mv -v "${i}" "${i%.*}_MYSUFFIX.${i##*.}"
done

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