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Hey I have a problem with regular subexpresions.
grep -o ".*='.*'" parameters.txt
parameters.txt includes:
name='something'
lastname=' 123123'
something=' somethinggg'
My regular expresion returns everything, but i want it to return only name and value without = and ' '. I also want it to be immune to spaces and tabulators.
name something
lastname 123123
somethign somethinggg
In your case, I would recommend using sed instead:
sed -r "/^[^=]*$/d;t;s/=/ /;s/'//g;s/[\t ]+/ /g" parameters.txt
This command
= sign= by a space (leaving it open that the "value" part may itself contain an assignment)' by nothing= sign.
sed -e 's/['\''=]/ /g;s/ */ /g'
$ tr '=' ' ' < parameters.txt | sed "s,',,g" | sed -E "s,\s+, ,g"
name something
lastname 123123
something somethinggg
sed commands into one. Many sed dialects do not support the Perl escape \s (try [[:space:]] for a portable equivalent). Also, notice that sed has a y command; but replacing all equals slgns will wreck any value which contains a literal equals sign.
Using Perl:
perl -pe "tr/=' \t/ /d" parameters.txt
=also contain=-characters? What does the "immunity" actually mean? Does it mean you want to allow the line to be indented by spaces or tabs (should the indentation be preserved in that case?), or does it mean you want to maintain any spaces or tabs in the values to the right?