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I have a directory called 'directory1' with files: file1, file2, file3, that have been passed by in a variable 'files'. Echo $files has the following output: file1 file2 file3. I want to have the sum of the sizes but the code below only works for only one file. How can I make it work for all the files?
ls -l ./$dir/$files | awk '{t+=$5}END{print t}'
You could print the files sizes in bytes using a loop with stat and sum the output with awk:
for i in $files; do
stat -c '%s' "$dir/$i"
done | awk '{t+=$1}END{print t}'
for i in "$files"; do stat -c '%s' "$dir/$i"; done?
stat -c '%s' "$dir/$i" is easier. But $files should be unquoted if the filenames are space separated. Thanks @terdon.
set -f to turn off filename globbing and set IFS=' ' to avoid splitting the filenames on anything other than spaces. How you would handle filenames with spaces, I don't know.
You can do it various ways :
First change into the directory and from there run the commands + turnoff glob expansion since the $file is uncovered.
cd "$dir" ;set -f
stat -c '%s' $files | paste -sd+ | bc -l
du --apparent-size -abc $files | tail -n 1
perl -E '$s += -s for @ARGV;say $s' $files
ls -l ./$dir/$filesitself is only going to give the file size of directory1/file1. Try it.filesvariable? You also mention adirvariable that is not described before. Does it mean that files are not on the same folder? Also is it required to useawkto sum the sizes or can other tools be used too?filesvariable, not the files themselves, like if they are full paths, separated by lines or just filenames separated by spaces, as examples. Usually we provide an example input as well as a desired output on such questions, so that the answer can be clear and straightforward. Could you add that to the question?