Sed replace regex pattern with nothing

Question

Hey so I want to replace a regex pattern with nothing, I've tried multiple sed routes but none seem to be working, i.e

sed -i 's/\.\d{1,3}\b$//'

Example of input,

Hello.123
Hello.123.90

expected output would be,

Hello
Hello.123

So what are you trying to match? You've shown us a regex that does not do what you want, but you haven't explained what you need. Are you trying to remove the last . followed by 1 to 3 numbers from each line? What if a line is foo.1234? Should we leave that unchanged? — terdon, Dec 5, 2019 at 0:49
Yes I want to remove the last dot followed by 1 to 3 numbers from each line. — Valkyrie, Dec 5, 2019 at 0:52
OK, so what happens with foo.1234? Nothing? Do we just print the line? — terdon, Dec 5, 2019 at 0:53

schrodigerscatcuriosity · Accepted Answer · 2019-12-05 00:52:54Z

1

Maybe yo can try something like this:

sed -i -E 's/\.[0-9]{1,3}$//' file

answered Dec 5, 2019 at 0:47

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