How to run grep with multiple AND patterns?

Question

I would like to get the multi pattern match with implicit AND between patterns, i.e. equivalent to running several greps in a sequence:

grep pattern1 | grep pattern2 | ...

So how to convert it to something like?

grep pattern1 & pattern2 & pattern3

I would like to use single grep because I am building arguments dynamically, so everything has to fit in one string. Using filter is system feature, not grep, so it is not an argument for it.

---

Don't confuse this question with:

grep "pattern1\|pattern2\|..."

This is an OR multi pattern match. I am looking for an AND pattern match.

Answer 1

To find the lines that match each and everyone of a list of patterns, agrep (the original one, now shipped with glimpse, not the unrelated one in the TRE regexp library) can do it with this syntax:

agrep 'pattern1;pattern2'

With GNU grep, when built with PCRE support, you can do:

grep -P '^(?=.*pattern1)(?=.*pattern2)'

With ast grep:

grep -X '.*pattern1.*&.*pattern2.*'

(adding .*s as <x>&<y> matches strings that match both <x> and <y> exactly, a&b would never match as there's no such string that can be both a and b at the same time).

If the patterns don't overlap, you may also be able to do:

grep -e 'pattern1.*pattern2' -e 'pattern2.*pattern1'

The best portable way is probably with awk as already mentioned:

awk '/pattern1/ && /pattern2/'

Or with sed:

sed -e '/pattern1/!d' -e '/pattern2/!d'

Or perl:

perl -ne 'print if /pattern1/ && /pattern2/'

Please beware that all those will have different regular expression syntaxes.

Answer 2

You didn't specify grep version, this is important. Some regexp engines allow multiple matching groupped by AND using '&' but this is non-standard and non-portable feature. But, at least GNU grep doesn't support this.

OTOH you can simply replace grep with sed, awk, perl, etc. (listed in order of weight increasing). With awk, the command would look like

awk '/regexp1/ && /regexp2/ && /regexp3/ { print; }'

and it can be constructed to be specified in command line in easy way.

Answer 3

grep pattern1 | grep pattern2 | ...

I would like to use single grep because I am building arguments dynamically, so everything has to fit in one string

It's actually possible to build the pipeline dynamically (without resorting to eval):

# Executes: grep "$1" | grep "$2" | grep "$3" | ...
function chained-grep {
    local pattern="$1"
    if [[ -z "$pattern" ]]; then
        cat
        return
    fi    

    shift
    grep -- "$pattern" | chained-grep "$@"
}

cat something | chained-grep all patterns must match order but matter dont

It's probably not a very efficient solution though.

Answer 4

git grep

Here is the syntax using git grep combining multiple patterns using Boolean expressions:

git grep --no-index -e pattern1 --and -e pattern2 --and -e pattern3

^{The above command will print lines matching all the patterns at once.}

--no-index Search files in the current directory that is not managed by Git.

Check man git-grep for help.

See also:

• How to use grep to match string1 AND string2?
• Check if all of multiple strings or regexes exist in a file.

For OR operation, see:

• How do I grep for multiple patterns with pattern having a pipe character?
• Grep: how to add an "OR" condition?

Answer 5

If patterns contains one pattern per line, you can do something like this:

awk 'NR==FNR{a[$0];next}{for(i in a)if($0!~i)next}1' patterns -

Or this matches substrings instead of regular expressions:

awk 'NR==FNR{a[$0];next}{for(i in a)if(!index($0,i))next}1' patterns -

To print all instead of no lines of the input in the case that patterns is empty, replace NR==FNR with FILENAME==ARGV[1], or with ARGIND==1 in gawk.

These functions print the lines of STDIN which contain each string specified as an argument as a substring. ga stands for grep all and gai ignores case.

ga(){ awk 'FILENAME==ARGV[1]{a[$0];next}{for(i in a)if(!index($0,i))next}1' <(printf %s\\n "$@") -; }
gai(){ awk 'FILENAME==ARGV[1]{a[tolower($0)];next}{for(i in a)if(!index(tolower($0),i))next}1' <(printf %s\\n "$@") -; }

Answer 6

Here's my take, and this works for words in multiple lines:

Use find . -type f followed by as many
-exec grep -q 'first_word' {} \;
and the last keyword with
-exec grep -l 'nth_word' {} \;

-q quiet / silent
-l show files with matches

The following returns list of filenames with words 'rabbit' and 'hole' in them:
find . -type f -exec grep -q 'rabbit' {} \; -exec grep -l 'hole' {} \;

Answer 7

to search multiple files for the presence of two patterns anywhere in the file use

awk -v RS="" '/patern1/&&/patern2/{print FILENAME}' file1 ... filen

Answer 8

ripgrep

Here is the example using rg:

rg -N '(?P<p1>.*pattern1.*)(?P<p2>.*pattern2.*)(?P<p3>.*pattern3.*)' file.txt

It's one of the quickest grepping tools, since it's built on top of Rust's regex engine which uses finite automata, SIMD and aggressive literal optimizations to make searching very fast.

^{See also related feature request at GH-875.}

Answer 9

To find all of the words (or patterns), you can run grep in a for loop. The main advantage here is searching from a list of regular expressions.

A real example:

# File 'search_all_regex_and_error_if_missing.sh'

find_list="\
^a+$ \
^b+$ \
^h+$ \
^d+$ \
"

for item in $find_list; do
   if grep -E "$item" file_to_search_within.txt
   then
       echo "$item found in file."
   else
       echo "Error: $item not found in file. Exiting!"
       exit 1
   fi
done

Now let's run it on this file:

hhhhhhhhhh
aaaaaaa
bbbbbbbbb
ababbabaabbaaa
ccccccc
dsfsdf
bbbb
cccdd
aa
caa

$ ./search_all_regex_and_error_if_missing.sh
aaaaaaa aa
^a+$ found in file.
bbbbbbbbb bbbb
^b+$ found in file.
hhhhhhhhhh
^h+$ found in file.
Error: ^d+$ not found in file. Exiting!