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I have the following job in my crontab:
0 */4 * * * /usr/bin/mysqldump -u root -p'PASSWORD' --all-databases | /bin/gzip -9 > /home/USER/_mysql_backup/`date "+\%F--\%H-\%M"`.databases.sql.gz ; rm -f /home/USER/_mysql_backup/`date '+\%F' --date '1 week ago'`.databases.sql.gz >/dev/null 2>&1
The problem is that it's filling up my syslog. I thought adding >/dev/null 2>&1 would prevent the job from being logged, but do I also need to add it for the previous command before the ; ?
If the command in the crontab writes anything to stdout, then cron will take that output and try to mail it to you. Apparently you have no MTA installed, so cron fails to send a mail message and logs that failure to the log file.
If you want to see what the cron job is writing to its stdout, then you have to install an MTA: cron will mail you that output and will presumably not log anything since the sending of the mail will succeed.
If you don't want to see the output, then redirect it to /dev/null. I would still set up an MTA though, so that cron will be happy even when some cron job produces output unexpectedly.
The crond(8) manpage describes the details.
rm -f [...]to/dev/null. What do you see in the log?CRON[22446]: (CRON) info (No MTA installed, discarding output)CRON[22471]: (user) CMD (/usr/bin/mysqldump -u root -p'PASSWORD' --all-databases | /bin/gzip -9 > /home/USER/_mysql_backup/date "+%F--%H-%M".databases.sql.gz ; rm -f /home/USER/_mysql_backup/date '+%F' --date '1 week ago'.databases.sql.gz >/dev/null 2>&1)cronsimply logs what it executes. Your question should read "how do I stop cron from logging executed commands?"