Substring is bash script to matching correctly

Question

I have a bash script that has a filename and a string contained within a file and I want to compare a substring from the file against the filename(tar.gz) to see if they match or not.

substr=$(echo "$(cat /home/user/configrc | grep Version)" | cut -d '_' -f4-5)
xfile="/home/user/data_1806_01.tar.gz"
echo $substr
echo $xfile
echo "Is $substr in $xfile"

if [ "$xfile" == *"$substr"* ]; then echo "Match"; else echo "No Match"; fi

the output is as follows

DD_DATA_AB_1806_01
1806_01
/home/user/data_1806_01.tar.gz
 in /home/user/data_1806_01.tar.gz
No Match

I can't get a match to occur, 1806_01 should have the substring match in DD_DATA_AB_1806_01. Also what is strange is that the line - echo "Is $substr in $xfile" does not get printed out properly - "Is $substr" or "Is 1806_01" is missing

Is there some sort of termination that i need at the end of substr??

The file configrc contains the line Version=DD_DATA_AB_1806_01

I have looked at many examples online but can't see what I am doing wrong.... such a simple problem....

Thank you very much :)

Centos 7.2

Answer 1

As mentioned in the comments, you don't need echo and cat to grep for the string and you need two brackets for this type of comparison:

substr=$(grep 'Version' /home/user/configrc | cut -d '_' -f4-5)
xfile="/home/user/data_1806_01.tar.gz"

if [[ "$xfile" == *"$substr"* ]]; then
  echo "Match"
else
  echo "No Match"
fi