I have this line of code for the shell:

ls -1 *.mp3| awk -v here="$(cygpath -w $PWD)" -v source="$source" '{print "File Name: "$0"\n"here"\n"source}'

Unfortunately it outputs:

File Name: Data 00053.mp3
Source: Converted from RAW

This line C:UsersathenaWorkProject_10.MBT Should be C:\Users\athena\Work\Project_10\00.MBT

I am now lost, a lot to learn here.

  • 1
    See also cygpath -aw . for the current working directory in Windows format. Commented Sep 19, 2019 at 9:28

1 Answer 1


That's an issue relating to how awk treats the value passed using -v. It interprets the backslashes in the passed string.

Instead, pass it through an environment variable:

here="$(cygpath -w "$PWD")" awk ... '{ print ... ENVIRON["here"] ... }'

ENVIRON is an associative array in awk that contains the values of the variables in the current environment, keyed by name.

Also related to your code:

  • It solved the issue for sure.
    – Ken Ingram
    Commented Sep 19, 2019 at 21:43
  • It doesn't work for multiple variables though. Any thoughts?
    – Ken Ingram
    Commented Sep 20, 2019 at 1:04
  • 1
    @KenIngram Did you try? a=1 b=2 c=3 awk 'BEGIN { print ENVIRON["a"], ENVIRON["b"], ENVIRON["c"] }'. You could obviously just export the variables instead of assigning them on the same command line as awk (but that would make them part of your script's environment too).
    – Kusalananda
    Commented Sep 20, 2019 at 5:27

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .