0

I have a large file.

How can I print every 9th line starting at line 6?

awk NR % 9 == 0' file1 > file2
4

In GNU sed you can use the first~step operator:

sed -n '6~9p' file1 > file2
0

Use a variable (lin) which holds the line number, from line 6. If lin is a multiple of 9 then print the line with the line number.

awk '{lin=NR-6; if (!(lin %9)) print}' file1 > file2

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