As the memory segments are part of Linux operating system, is it possible to view their respective addresses using simple C program or any linux commands.
If you wrote a program and you want to see its memory mapping when it's running, you can run it in a debugger like gdb, then start it, and take a look at the memory map with the command info proc mappings, the output will be something like this:
(gdb) info proc mappings
process 6520
Mapped address spaces:
Start Addr End Addr Size Offset objfile
0x10000 0x15000 0x5000 0x0 /bin/true
0x24000 0x25000 0x1000 0x4000 /bin/true
0x25000 0x26000 0x1000 0x5000 /bin/true
0x76e6e000 0x76f98000 0x12a000 0x0 /lib/arm-linux-gnueabihf/libc-2.24.so
... etc ...
0x7efdf000 0x7f000000 0x21000 0x0 [stack]
0xffff0000 0xffff1000 0x1000 0x0 [vectors]
If you instead want to see the mappings of an already running process you can, assuming that you have the right permissions, do cat /proc/<pid>/maps. In alternative you could attach to the process with gdb -p <pid> and do what I explained above.
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0x7efdf000 0x7f000000 0x21000 0x0 [stack]. Small query here. Does this address range refers only the particular process or the whole operating system's stack. – renga_in_stack Sep 2 '19 at 7:34
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2There's no such thing as "the whole operating system stack". Each process has its own stack mapped in its virtual memory space. – Marco Bonelli Sep 2 '19 at 7:34
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Ok got ur point. I was not aware of virtual memory concepts. So i got confused little bit earlier. – renga_in_stack Sep 2 '19 at 7:41
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@renga_in_stack if this correctly answered your question, please accept the answer by clicking on the green mark on the top left near the vote buttons, so that this question can be marked as solved. – Marco Bonelli Sep 2 '19 at 8:55
gdbfor example. – Kusalananda♦ Sep 2 '19 at 7:08