I want to schedule a job for 3rd Friday of every month, 1 AM . I checked few cron entry websites for that didn't work for me.

I was also checking for some awk options for this so far not successful with that. Can you guys help me with that?

I tried to run this for today the cron is working fine but the script is running continuously at the same point and not getting completed :

0 1 15-21 * * test $(date +\%u) -eq 5 && echo "3rd friday" && Extract_Param.sh /landing/file/ABC/file.txt 

1 Answer 1


Unfortunately, when you give both a day-of-month and a day-of-week in a crontab entry, this means either one is sufficient. (Didn't know that either, but the manpage says so.) This means we can't simply calculate that the 3rd friday is a friday that is between the 15th and 21st of the month.

Fortunately, the above-linked man page also advises us:

One can, however, achieve the desired result by adding a test to the command (see the last example in EXAMPLE CRON FILE below).


# Run on every second Saturday of the month
0 4 8-14 * *    test $(date +\%u) -eq 6 && echo "2nd Saturday"

so you should be fine with

0 1 15-21 * *    test $(date +\%u) -eq 5 && echo "3rd friday"
  • So this is how i put the entry as i am passing an argument to ithe script i have to schedule? 0 1 15-21 * * test $(date +\%u) -eq 5 && echo "3rd friday" && Extract_Param.sh /landing/file/ABC/file.txt Aug 16, 2019 at 7:14
  • Can you please tell me if there is any error in the cron entry? Aug 16, 2019 at 9:51
  • @user3901666: well, you should leave off the && echo "3rd friday", other than that, that looks good. Aug 16, 2019 at 12:34
  • But, I was able to get the cron run with your command , I just had to add a sh before the script. Thank you so much. Aug 16, 2019 at 13:34
  • 1
    @user3901666: Yes, the first (day-of-week) of the month will always be in days 1-7, because day 8 is the same as day 1. 8-14 are the second occurences, 15-21 the third, 22-28 the fourth. Aug 19, 2019 at 6:08

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