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Hello I have a bunch of folders with several images (jpg and png) at the same directory level (./ParentDirectory/contents/1680x1050.png for example) called the same (1680x1050.jpg or 1680x1050.png) on different subdirectories,

I want to know if it's possible to use the find command to copy this files to a different directory (e.g. ./Something/) keeping the name but adding the parent name to the file name so at the end they are as ./Something/ParenDirectory_1680x1050.jpg and ParenDirectory_1680x1050.png.

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After cding to the parent directory of ParentDirectory, run:

find ParentDirectory -type f \( -name "1680x1050.png" -o -name "1680x1050.jpg" \) \
  -exec sh -c 'cp "$1" "Something/${1%%/*}_${1##*/}"' sh {} \;

In the -exec part where a new shell process is executed for each png or jpg found, the path to the image {} is passed as argument $1 to the shell script.

In the cp command the target filename is put together and ${1%%/*} is used to get the parent directory name removing the longest suffix pattern (everything after the first /) and ${1##*/} is used to get the filename part removing the longest prefix pattern (all characters until the last /).

To achieve the same result executing only one shell process for all images found, you could use

find ParentDirectory -type f \( -name "1680x1050.png" -o -name "1680x1050.jpg" \) \
  -exec sh -c 'for i; do cp "$i" "Something/${i%%/*}_${i##*/}"; done' sh {} +

and loop through all filename arguments in the script with a for-loop.

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