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I am trying to get usernames from /etc/passwd if UID equal/greater than 1000 using a for loop. The below simple bash script works but prints the username twice for some reason.
#!/bin/bash
for userid in `awk -F: '{print $3}' /etc/passwd`
do
if (("$userid" >= 1000)); then
echo "Valid User" :`cat /etc/passwd | grep $userid | awk -F: '{print $1,$3}'`
fi
done
try this,
awk -F ':' '$3>=1000 {print "Valid User :"$1","$3}' /etc/passwd
maybe you might have the user IDs like 1000 and 10001. So your grep leads to duplicate while iterating in for loop.
Try as
echo "Valid User" :`cat /etc/passwd | grep ":$userid:" | awk -F: '{print $1,$3}'`
grep XX it will get you both XX and XXX. So you should have boundaries to iterate properly like grep "\bXX\b" or with a static string which I used in the answer as grep ":$userid:"
3 and not $3 before muru edited it, your answer prints the username and then a comma and the number 3 when he wants it to print the username and the userid.
Aug 3, 2019 at 6:09
awk -F : '$3 >= "1000" {print "Valid User " $1,$3}' /etc/passwd?awk -F : '$3 >= 1000 {print "Valid User " $1,$3}' /etc/passwd