Next command output on the same line? Bash script

Question

I have the following simple script:

echo "-------------------------- SOA --------------------------------"
echo " "
echo -n "  ---------> "; dig soa "$1" +short | awk '{print $3}'

The output is something like this:

-------------------------- SOA --------------------------------

---------> 2019072905

Now my question is can I make an "echo" command after the dig and the output to be something like this:

-------------------------- SOA -----------------------------

            ---------> 2019072905 <-------------

I have tried to search for similar cases but was not able to find any related.

Would this be possible?

Thanks in advance.

Answer 1

I would do the whole thing in printf instead:

#!/bin/sh

header='-------------------------- SOA --------------------------'

headerLength=$(awk '{print length()}' <<<"$header")

value=$(dig soa "$1" +short | awk '{print $3}')

valueString="-----------> $value <-------------"

valueLength=$(awk '{print length()}' <<<"$valueString")

offset=$(((headerLength + valueLength)/2+1))

printf "%s\n\n%${offset}s\n" "$header" "$valueString"

This has the advantage of always appearing centered no matter what the length of your value is (using a slightly modified version that just sets value=$1 to illustrate):

$ foo.sh 2019072905
-------------------------- SOA --------------------------------

            -----------> 2019072905 <-------------
$ foo.sh "some random long string"
-------------------------- SOA --------------------------------

      -----------> some random long string <-------------
$ foo.sh "foo"
-------------------------- SOA --------------------------

              -----------> foo <-------------

Answer 2

cmd=$(dig soa "$1" +short | awk '{print $3}'; echo -n \<----------;)

echo "-------------------------- SOA --------------------------------"
echo " "
echo -n "      ---------> ";echo $cmd

Answer 3

#!/bin/sh

soa=$(dig soa "$1" +short | awk '{print $3}')

cat <<__EOF__
-------------------------- SOA -----------------------------

            ---------> $soa <-------------
__EOF__

---

BTW, I think the question is wrong-headed because printing all that header garbage around the SOA just makes it pointlessly harder to use the output of this script as input to another script...and even when you don't currently think you'll ever need to do that, in future you might. Verbosity in output is a "sin" in unix :) - when writing a script, you should always be thinking that your output could end up being someone else's (including yourself) input.

I would have ignored the question, but I disliked the other answer even more. If you're going to do something wrong, you may as well do it properly.

Answer 4

I don't have dig so used echo in it's place for this example:

$ echo '2019072905' | awk '
    BEGIN { d=sprintf("%15s",""); gsub(/ /,"-",d); print d d, "SOA", d d ORS }
    { printf "%*s> %s <%s\n", 2*length(d)-length($0)/2+1, d, $0, d }
'
------------------------------ SOA ------------------------------

           ---------------> 2019072905 <---------------

$ echo '201' | awk '
    BEGIN { d=sprintf("%15s",""); gsub(/ /,"-",d); print d d, "SOA", d d ORS }
    { printf "%*s> %s <%s\n", 2*length(d)-length($0)/2+1, d, $0, d }
'
------------------------------ SOA ------------------------------

              ---------------> 201 <---------------

$ echo '12345672019072905' | awk '
    BEGIN { d=sprintf("%15s",""); gsub(/ /,"-",d); print d d, "SOA", d d ORS }
    { printf "%*s> %s <%s\n", 2*length(d)-length($0)/2+1, d, $0, d }
'
------------------------------ SOA ------------------------------

       ---------------> 12345672019072905 <---------------