bash script select menu

Question

I've many notes gleaned from the web and have written bash scripts to manage them.

I've some scripts working that depend on select to make menus.

Question: in a nested menu context, is it possible to revert to a preceding menu within the script ? I've a strong feeling that this may not be possible but am posting this in the hope there may be a way.

To explain what I mean: say the user makes a choice against menu-1 which then determines what shows up in menu-2 which follows. If the user selects "done" in menu-2, is there a loop device to bring the user back to menu-1 ?

The script below contains 3 selects - I'd like to be able to revert from the 3rd one back to the 2nd:

curd=($(ls)); # array

select dirup in ${curd[@]} done 

do


cd $dirup;
    ar=($(ls | awk -F"." '{ print $1 }' | awk -F"-" '{ for(i=2; i<=NF; i++) print $i }' | sort | uniq)); 


select choice in ${ar[@]} done # select list
    do 
        echo "you selected: $choice"
        [[ $choice == "done" ]] && exit 
        ar=($( find . -type f -maxdepth 1 -name "*$choice*" ));
        ((cnt=${#ar[@]}+1))
        select ntit in ${ar[@]} done
            do 
                echo "choice is:[ $REPLY ]"
                for i in $REPLY; # $REPLAY contains numbers
                    do
                      if [ $i -lt $cnt ]
                        then 
                            ((var=$i-1)); 
                            open ${ar[$var]}; 
                        else 
                            exit
                      fi
                    done

            done

      done

done

Answer 1

Use break instead of exit. Note, though, that the menu is not reprinted when returning to a higher menu.

Example:

select x in nothing inner quit ; do
    [[ $x == quit ]] && break
    if [[ $x == inner ]] ; then
        select y in NOTHING BACK ; do
            [[ $y == BACK ]] && break
        done
    fi
done