sed find and replace string

Question

I have these lines in multiple files:

<update>2013-02-10</update>
<version>1.15</version>

and I want to replace them with (new date and version):

<update>2019-06-30</update>
<version>1.28</version>

How can do this on multiple files using sed or awk? (I'm on Mac OS)

edit 1: lines <update> and <version> are not one after another and I want to replace every occurrence of them.

edit 2: date varies but the string <update>doesn't get changed, so I can't use find "2013-02-10" and replace with "new date"

Answer 1

sed -i backup -E '/<update>/s/[0-9]{4}-[0-9]{2}-[0-9]{2}/2019-06-30/;/<version>/s/[0-9]\.[0-9]{1,2}/1.28/' *

• -i backup means to edit the files at their place, but keep a backup file with extension backup. You can delete them if the command did what you expected. If it did something else you'll be happy to have the backups!
• -E is for extended regular expressions. Makes the script more readable because you don't need to escape the {}
• For each line with pattern /<update>/ do s/[0-9]{4}-[0-9]{2}-[0-9]{2}/2019-06-30/ which is replacing a date string ####-##-## with the given date
• For each line with pattern /<version>/ do s/[0-9]\.[0-9]{1,2}/1.28/ which is replacing the version string #.# or #.## with the given version

Answer 2

If you don't mind typing in two commands, you can use:

sed -i 's/\<update\>2013-02-10\<\/update\>/2019-06-30\<\/update\>/g' *

sed -i 's/\<version\>1.15/1.28\<\/version\>/g' *

In the home directory of where the files are.

Alternatively, if you want it to execute recursively:

find ./ -type f -exec sed -i 's/\<update\>2013-02-10/2019-06-30\<\/update\>/' {} \;

find ./ -type f -exec sed -i 's/\<version\>1.15/1.28\<\/version\>/' {} \;