Replacing with sed expression [closed]

Question

I'm trying to get a value such as

"909,999"

With this (the example is replacing it with nothing):

sed 's/["][0-9]+[,][0-9]+["]//g'

But it's not working.

Answer 1

If you want to replace the pattern, you can use sed -E or escape the + characters as suggested by @Kusalananda:

$ printf '"123.456"\n"909,999"\n"100"\n' | sed -E 's/"[0-9]+,[0-9]+"//g'
"123.456"

"100"

or

$ printf '"123.456"\n"909,999"\n"100"\n' | sed 's/"[0-9]\+,[0-9]\+"//g'
"123.456"

"100"

Note that the g is not needed in this example as there is only one substitution per line.

If you want to delete the matching line(s), you could use d to delete the pattern space:

$ printf '"123.456"\n"909,999"\n"100"\n' | sed '/"[0-9]\+,[0-9]\+"/d'
"123.456"
"100"