So some background first: I am attempting to convert a non-encrypted shared folder into an encrypted one on my Synology NAS and am seeing this error:

Synology NAS Error

So I would like to locate the offending files so that I may rename them. I have come up with the following grep command: grep -rle '[^\ ]\{143,\}' * but it outputs all files with paths greater than 143 characters:

#recycle/Music/TO SORT/music/H/Hooligans----Heroes of Hifi/Metalcore Promotions - Heroes of Hifi - 03 Sly Like a Megan Fox.mp3

What I would like is for grep to split on / and then perform its search. Any idea on an efficient command to go about this (directory easily contains hundreds of thousands of files)?


3 Answers 3


Although the GNU ‘findutils-default’ regular expression syntax doesn't provide a {n,m} interval quantifier, you can use a -regex test in GNU find if you select a different regextype, for example:

find . -regextype posix-extended -regex '.*/[^/]{143,}$'


find . -regextype egrep -regex '.*/[^/]{143,}$'


find . -regextype posix-basic -regex '.*/[^/]\{143,\}$'

etc. There may be other regextypes that support {n,m} intervals, either with or without escaping.

Compared to piping the results of find to a separate grep command, this will match across newlines (i.e. the find regex flavors differ from their namesakes in that . matches the newline character by default).



find /your/path | grep -E '[^/]{143,}$'

If you've already got a locate db, it is very fast at this.

locate --regex '.*/[^/]{143,}$'

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