Unzipping the parent directory contents ignoring sub-directory and their contents

Question

I am unzipping the .zip file. I'm able to do so but my requirement to extract only the parent folder data ignoring any sub directory and their contents.

Below is the name format of zip file.

filename.csv.zip

commands I have used unzip -j /zip_filepath "*" -d /final_directory.

I tried with above commands but above commands extracting all the complete zip contents which are the part of zip file.

Please find below the file structure of zip file.

• -rw-r--r-- abc.csv
• drwxrwxr_x __MACOSX/
• -rw-r--r-- __MACOSX/_abc.csv

Second zip file structure: *-rw-r--r-- xyz.csv

I want to extract only abc.csv and xyz.csv files from the zip files.

---

Output of: unzip -Z -1 abc.zip

__MACOSX/
__MACOSX/_abc.csv
abc.csv

---

Output:unzip -Z -1 /user/sam/abc.zip -d /user/sam/2019-05-22/

caution: not extracting -d ignored

    abc.csv
    __MACOSX
    __MACOSX/._abc.csv

The output here should be abc.csv file only

Output of: unzip -Z -1 xyz.zip

xyz.csv

---

Output:unzip -Z -1 /user/sam/xyz.zip -d /user/sam/2019-05-22/

caution: not extracting -d ignored
xyz.csv

Answer 1

You can use -x option, with '*/*' as argument, like this:

unzip filename.csv.zip -x '*/*' -d /final_directory

If you want to suppress the Warning caution: excluded filename not matched: */* for cases like the one with your xyz.zip file, you can use:

unzip filename.csv.zip -x '*/*' -d /final_directory 2> /dev/null

Note: bare in mind that this will suppress all of stderr output. It would be ideal to instruct unzip command to not show that kind of warning (only that kind),... I took a quick look at its manual, and I did not see any option for that. So, in your case, if is not possible to instruct unzip to just suppress that kind of warning, I think is better to suppress nothing at all, cause that warning it's making no harm, but if you discard all errors, you could miss some important information.