How to group a string that has multiple words with awk? (Prints lines between 2 patterns)

Question

I have an issue in which my string its not a single string; it is a string with multiple words; in which using sed works great; but not with awk;

How can I group all that string with awk? I tried to encapsulate the string with " ", with { }, with ( ) and nothing works. Here is the example of my sed vs awk:

sed -n '/show system | inc Software/,/sh syst | i @@@@@/p' filename.txt > out_file.txt

That line works perfect with sed; the strings are "show system | inc Software" and "sh syst | inc @@@@@"

As for awk it doesnt work.

awk '/show system | inc Software/,/sh syst | i @@@@@/' filename.txt > out_file.txt

The output file is not what I expect. How can I do that strings to work in that command?

Answer 1

Your question will be easier to understand if you include your input data and expected output data.

The following awk command will print the lines 'show system | inc Software' and 'sh syst | i @@@@@' and every line in-between:

awk '/show system \| inc Software/,/sh syst \| i @@@@@/{n=0}' filename.txt > out_file.txt

Edit:

Also, it looks like your sed command won't work, (assuming I've understood your question) it should be:

sed -n '/show system | inc Software/,/sh syst | i @@@@@/p' filename.txt > out_file.txt